# CoCubes Logarithms Question and Answers Quiz-1

Question 1

Time: 00:00:00
If logx (0.1) = -1/3, then the value of x is -

10

10

1000

1000

10000

10000

100

100

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Question 2

Time: 00:00:00
If ax = by, then :-

log(a/b) = x/y

log(a/b) = x/y

log(a) / log(b) = x/y

log(a) / log(b) = x/y

log(a) / log(b) = y/x

log(a) / log(b) = y/x

None of these

None of these

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ax=by then a/b=y/x so log(a/b)=log(y/x)

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Question 3

Time: 00:00:00
If log8 x + log8 (1/6) = 1/3 then, the value of x will be:

18

18

16

16

12

12

24

24

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Question 4

Time: 00:00:00
If log x + log y = log (x + y), then which statement follows:

y = x/(x-1)

y = x/(x-1)

xy=1

xy=1

y = (x-1)/x

y = (x-1)/x

x = y

x = y

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Question 5

Time: 00:00:00
If log10 7 = a, then log10(1/70) will be equal to:

1/10a

1/10a

(1 +16 a)-1

(1 +16 a)-1

a/10

a/10

-(1 + a)

-(1 + a)

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Question 6

Time: 00:00:00
If log{(a+b)/3} = 0.5(log a + log b), then the correct relation between a and b will be:

a2+b2 = 7ab

a2+b2 = 7ab

a2-b2 = 7ab

a2-b2 = 7ab

(a+b)2 = 2

(a+b)2 = 2

(a+b)/3 = (1/2)(a+b)

(a+b)/3 = (1/2)(a+b)

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Question 7

Time: 00:00:00
If log x = log 3 + 2 log 2- (3/4) log 16. The value of x will be:

4

4

1

1

2

2

3/2

3/2

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Question 8

Time: 00:00:00
If log10000 x = -1/4, then the value of x is:

1/10

1/10

1/100

1/100

1/1000

1/1000

1/40

1/40

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Question 9

Time: 00:00:00
The value of 3-1/2 log3(9) will be:

2

2

3

3

43134

43134

4

4

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Question 10

Time: 00:00:00
Which of the following statements is not correct?

$log_10{10} = 1$

$log_10{10} = 1$

log (2 + 3) = log (2 x 3)

log (2 + 3) = log (2 x 3)

$log_10{1} = 0$

$log_10{1} = 0$

log (1 + 2 + 3) = log 1 + log 2 + log 3

log (1 + 2 + 3) = log 1 + log 2 + log 3

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