Quiz 1

a=-1 (non zero integer) so, if condition becomes true hence, b will get printed  on the output screen.

End if is used to close the If block in pseudocodes

Indentation is used to show hierarchy in a pseudo code.

<< is the left shift operator x<<y is equals to x*(2^y) so, 10<<2 = 10(2^2) = 40.

 Initially x=10 , y= x++ (post increment operator) first y is assigned with value 10 then x will gets increment by 1

So, the output will be 11 10.

Initially a = 10 and b=20, As the associativity of the assignment operator is right to left so c is assigned with 30, then y assigned with 30 and at last x is assigned with 30.

^ is the bitwise XOR operator and will return 1 only if the bits are different so 8^8 will return 0.

>> is the bitwise right shift operator x>>y is equal to x/(2^y) so, 10>>2 = 10/(2^2) = 2.

When the value of c becomes 1, in the condition c-- will make it 0. So when n divides by 0 it gives runtime error.

 

 Initially x is set with 10 and y=2 when x=x/y then x = 5, z= x<<y (bitwise left operator is used so z = x*(2^y))  => z=20.