Wiley Edge Profit and Loss Quiz-3

Consider the C.P. = Rs.100

then, marked price will be = Rs.150

S.P. = 75% of Rs.150

S.P. = (75/100) * 150 = Rs.112.50

i.e) gain = 12.50%

Let the marked price of each pen be Re.1

then, C.P. of 40 pens will be = Rs.36

S.P. of 40 pens = 99% of Rs.40

S.P. of 40 pens = (99/100) * 40 = Rs.39.60

profit% = ((39.60 - 36)/36) * 100% = 10%

Total cost incurred = (600 × 40,000) + (500 × 35,000)
= 24000000 + 17500000
= 41500000 = 41.5 million [1 million = 1000000]

Total units = 600 + 500 = 1100
Total Revenue = 1100 × 50,000 = 55 million.

Profit % = \frac{Revenue-Cost}{Cost}\times100
Profit % = \frac{55million-41.5million}{41.5million}\times100
\frac{13.5}{41.5}\times 100 = 32.5%

C.P of a FibreSpoons = Rs. 4
S.P. of a FibreSpoons before discount = 54 / 12 = Rs 4.5
S.P. of a FibreSpoons after discount = 4.5 × 0.9 = Rs. 4.05

Profit % after giving discount : Profit % without giving discount
\frac{4.05-4}{4}\times100 : \frac{4.5-4}{4}\times 100
= 4.05 – 4 : 4.5 – 4
= 0.05 : 0.5
= 1 : 10

Let the cost price of a Wooden Study Table be Rs X

The cost price of 150 Wooden Study Table = 150X

40% of them are damaged, then the remaining Wooden Study Table = 60% of 150 = 90
The selling price of 50% of remaining Wooden Study Table,
= 45\times (X+\frac{20X}{100})

The selling price of remaining 50% Wooden Study Table,
= 45\times (X-\frac{5X}{100})

Given that,
45(X+\frac{20X}{100})+ 45 (X-\frac{5X}{100})=7740
2X + \frac{20X}{100}-\frac{5X}{100}=\frac{7740}{45}
X = 80
Hence the cost price of 150 Wooden Study Table = 150X = 150 × 80 = Rs. 12000

Using the formula to determine the Cost price of the Lava Blaze 5G:
Since, The Lava Blaze 5G was sold at price 25 % more than its C.P. then it is 25 % profit.
(i.e. Gain % = 25 %)
S.P = 9852 Rs
C.P =\frac{S.P}{1+ \frac{Profit %}{100}}
C.P =\frac{9852}{1+ \frac{25}{100}}
C.P = 7881.6 Rs

Let the walnut sold at 10% gain = A
∴ Walnut sold at 20% gain = (10000 – A)

Let CP of Walnut = ₹ B per kg

Total CP = Rs 10000 B

∴(\frac{110}{100}\times A B) + \frac{120}{100}(10000-A)B = \frac{117}{100}\times 10000B
\frac{110\times AB + 1200000B - 120AB}{100}= \frac{117}{100}\times 10000B
{110\times AB + 1200000B - 120AB}={117}\times10000B
=110 AB + 30000 B - 120 AB
=30000B - 10AB
10AB = 30000B
A = \frac{30000}{10}
A = 3000 Rs
∴ Walnut sold at 20% gain = (10000 – A)
= 10000 - 3000
= 7000 Rs

Given, Cost Price of the Bike = Rs.43000, Profit % earned = 20 %
Applying the formula :
C.P =\frac{S.P}{1+ \frac{Profit %}{100}}
43000 =\frac{S.P}{1+ \frac{20}{100}}
S.P = 43000\times \frac{6}{5}
S.P =51,600 Rs

Let CP = X
According to the question,
580 – X = X – 410
Now,
2X = 580 + 410 = 990
X= Rs 495
Now, Half of 60 % of C.P = \frac{1}{2}\times \frac{60}{100}\times495 =Rs 148.5

Here, We can use Direct Method to find out,
Reduced Cost = \frac{A \times X}{100 \times n}
Where, A = Rate of increased quantity = 90 Rs
X = Total discount applied = 25 %
n = Increased quantity rate = 4 Kg
Reduced Cost resulting Gain = \frac{90 \times 25}{100 \times 4}
= Rs 5.62 per Kg
Now, Original Price per Kg of Mango = \frac{A \times X}{(100 - X) \times n}
= \frac{90 \times 25}{(100 - 25) \times 4}
= 7.5 Rs per Kg