Wiley Edge Ages Quiz-3

Solution: Let's assume the present ages of X and Y are 4x and 9x, respectively, where x is the common factor. Given that the sum of their ages is 65.
The equation: 4x+9x=65
Combining like terms, we get: 13x=65
Dividing both sides by 13, we find: x=5
So, the common factor is 5.
Now, we can find the present age of Y.
Y's age= 9x=9*5=45
Therefore, the present age of Y is 45.

Solution: The present ages of P and Q are in the ratio 10:15.
Given that P is 18 years old, we can set up the proportion \frac{18}{Q}= \frac{10}{15}.
Simplifying the proportion, we find Q = (18*15)/10.
Calculating further, Q = 27.
Therefore, Q's present age is 27 years.

Solution: Let's assume Tom's present age as 5x.
Jerry's present age = 3x
According to the given information, 5x-3x=12
Simplifying the equation, 2x = 12.
Dividing both sides by 2, x = 6.
Therefore, Tom's present age is 30, and Jerry's present age is 18.

Solution: (x+20)+4=2(x+2)+4
x +24=2x+8
x=16

Solution: A + 3 = 1/2 * (M + 3)
2A + 3 = M - - (1)
A + 5 = 1/3 * (J + 5)
3A + 10 = J
J = M + 12
3A - 2 = M - -(2)
Solve 1 & 2
A = 5

Solution: Let the present age of A be x and the present age of B be y.
According to the given information: (x-5)=3(y-5)
(A was thrice as old as B five years ago) x+y=35
(The sum of their ages is 35)
Solving these equations simultaneously, we find: x=20 and y = 15
Therefore, the present age of A is 20 and the present age of B is 15.

Solution: Let the present age of B be x
According to the given information: 30+10=2(x+10)
(Ten years from now, A will be twice as old as B)
Simplifying the equation, we get: 40=2x+20
2x=20
x=10
Therefore, B's present age is 10.

Solution:
Seven years ago, A was three times as old as B. This can be represented as A-7=3(B-7).
Five years later, A will be twice as old as B. This can be represented as A + 5 = 2(B+5).
By solving these equations simultaneously, we find that the present age of A is 43 years and the present age of B is 19 years.

Solution: Let the present age of B be x
According to the given information:
(50-5) = 3(x-5) (A was thrice as old as B five years ago)
Simplifying the equation, we get: 45 = 3x-15 3x=60
x=20
Therefore, B's present age is 20.

Solution: Let the present age of A be x and the present age of B be y.
According to the given information:
(x+10) = 2(y+10) (Ten years from now, A will be twice as old as B)
x+y=60 (The sum of their ages is 60)
Solving these equations simultaneously, we find: x=40 and y = 20
Therefore, the present age of A is 40 and the present age of B is 20