# TCS Divisibility Question Answer 4

Question 1 Time: 00:00:00
Number when successively divided by 5, 3, 2 gives remainder 0, 2, 1 respectively in that order. What will be the remainder when the same number is divided successively  by 2, 3, 5 in that order? 4, 3, 2

4, 3, 2

1, 0,4

1, 0,4

2, 1, 3

2, 1, 3

4, 1, 2

4, 1, 2

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Question 2 Time: 00:00:00
a,b,c,d,e are distinct numbers. if (75-a)(75-b)(75-c)(75-d) (75-e)=2299 then a+b+c+d= ? 292

292

119

119

339

339

129

129

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Question 3 Time: 00:00:00
265x is divisible by 5 then value of x will be zero or 5

zero or 5

5

5

zero

zero

7

7

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Question 4 Time: 00:00:00
How many 9 digit numbers are possible by using the digits 1, 2, 3, 4, 5 which are divisible by 4 if the repetition is allowed? $5^{8}$

$5^{8}$

$4^{7}$

$4^{7}$

$6^{9}$

$6^{9}$

$7^{2}$

$7^{2}$

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Question 5 Time: 00:00:00
What is the lowest possible integer that is divisible by each of the integers 1 through 7, inclusive? 411

411

420

420

470

470

658

658

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Question 6 Time: 00:00:00
If N=4P, where P is a prime number greater than 2, how many different positive even divisors does n have including n? 4

4

6

6

8

8

5

5

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Question 7 Time: 00:00:00
What is the remainder when 617+1176 is divided by 7? 1

1

6

6

3

3

zero

zero

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Question 8 Time: 00:00:00
The remainder when m + n is divided by 12 is 8, and the remainder when m - n is divided by 12 is 6.  If m > n, then what is the remainder when mn divided by 6? 3

3

4

4

2

2

1

1

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Question 9 Time: 00:00:00
X = 101102103104105106107......146147148149150

(From numbers 101-150).

Find out the remainder when this number is divided by 9. 1

1

2

2

3

3

4

4

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Question 10 Time: 00:00:00
Two positive number differ by 2001.When the larger number is divided by the smaller number, the quotient is 9 and the remainder is 41. The sum of the digits of the larger number is: 11

11

14

14

13

13

15

15

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