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Robert Bosch Time & Work Quiz-4

Question 1

Time: 00:00:00

Renuka can do a piece of work in 30 days.Vinu can do the same work in 24 days and Venkatesh in 40 days. Vinu and Venkatesh worked for 4 days and handed it to Renuka. Renuka worked for some days and handed it again to Vinu and Venkatesh 6 days before completing the work. For how many days did Renuka work?

5 days

6 days

8 days

10 days

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Answer: D
Explanation:
Work done by Vinu and Venketesh together in 4+6 (10) days = 10/24 + 10/40 = 2/3
Remaining work = 1 - 2/3 = 1/3
Renuka works for = 1/3 x 30 days = 10 days

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Question 2

Time: 00:00:00

Annu can build a wall in 8 days, Binod can do the same piece of work in 10 days while Chandu can do it in 12 days. They started work together but after 2 days Annu left the work and the remaining work was completed by Binod and Chandu. Find when the wall will be built (approx days)?

4 days

2 days

3 days

5 days

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Answer: A
Explanation: (Annu + Binod + Chandu)’s 1 day work = 1/8 + 1/10 +1/12 = 37/120
Work done by (Annu + Binod + Chandu) in 2 days = 2 x 37/120
Remaining work = 1 - 37/60 = 23/60
(Binod+Chandu) 1 day work = (1/10 + 1/12) = 11/60
Remaining work will be done by (Binod+Chandu) = 60/11 x 23/60 = 23/11 days ~ 2 days
So, the work will be finished approximately 2 days after Annu had left.i.e., around 4 days.
Hence the answer is 4 days.

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Question 3

Time: 00:00:00

Rohan makes toys at a rate such that he can finish making toys in 24 hrs, but he only works at this rate for 16 hrs. After that, he works at a rate such that he can do the whole work in 18 hrs. If Rohan is to finish this work at a stretch, how many hours will he take to finish this work?

12 hrs

18 hrs

15 hrs

22 hrs

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Answer: D
Explanation:
Rohan’s 16 hrs work = 16/24 = 2/3
Using Time and Work formula
He will complete all toys in =1/3 x 18 hrs = 6 hrs
Total time = 16 + 6 = 22 hrs.

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Question 4

Time: 00:00:00

Aman can do a piece of work in 60 days and Aman and Binod together can complete the work in 36 days. If Aman, Binod and Chandu together can complete the work in 15 days and they get the total wages 6000, then what is the wage of Binod?

1000

2000

3000

4000

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Answer: B
Explanation:
Let the total work be LCM of 60 and 36 = 180
Efficiency of Aman = 180/60 = 3
Efficiency of Aman + Binod = 180/36 = 5
Efficiency of Binod = 5 - 3 = 2
Combined efficiency of all three = 6
Efficiency of Chandu = 1
So the required ratio of A:B:C = 3:2:1
Hence, the wage of Binod = 2000 Rs

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Question 5

Time: 00:00:00

Amandeep and Binny can do a bit of work in 15 days. Binny and Chitra can do it in 30 days while Chitra and Amandeep can do it in 45 days. In how long will they complete if they work together Also, in how long can Amandeep alone do it?

90/11, 15

90/11, 30

100/11, 15

200/11, 15

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Answer: A
Explanation:
Let the total work be LCM of 15,30,45 = 90
Efficiency of Amandeep = 90/15 = 6
Similarly, Efficiency of Binny and Chitra = 3 and 2
So if they work together, Total time taken to finish the work = $\frac{90}{6+3+2}$ = 90/11
And Total time in which Amandeep can do the work alone = 90/6 = 15 days.

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Question 6

Time: 00:00:00

Two pipes A and B can fill a cistern in 15 and 30 minutes respectively, and a third pipe C can empty it in 60 minutes. How long will it take to fill the cistern if all the 3 pipes are opened at the same time?

12 mins

10 mins

15 mins

18 mins

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Answer: A
Explanation: 1/15 + 1/30 - 1/60 = 5/60 = 1/12 => 12 minutes

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Question 7

Time: 00:00:00

Pipe A can fill a tank in 12 minutes and pipe B can empty it in 32 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 48 minutes?

90 mins

94 mins

96 mins

102 mins

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Answer: D
Explanation: Let the pipe B be closed after x minutes.
48/12 – x/32 = 1 => 4 = 1 + x/32
=> x = 96 mins

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Question 8

Time: 00:00:00

3 pipes marked A, B and C can fill a tank from empty to full in 45 minutes, 30 minutes and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P, Q and R respectively. Find the ratio of solution R in the liquid in the tank after 5 minutes.

7/12

3/16

7/20

7/18

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Answer: D
Explanation: Part filled by (A + B + C) in 5 minutes = 5(1/45 + 1/30 + 1/10) = 7/9
Part filled by C in 5 minutes = 5/10 = 1/2
Required ratio = 1/2 * 7/9 = 7/18 will be the required ratio.

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Question 9

Time: 00:00:00

Two pipes M and N can fill a cistern in 30 minutes and 60 minutes respectively. Both pipes are opened. The cistern will be filled in just 20 minutes, if the B is turned off after

20 mins

30 mins

45 mins

15 mins

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Answer: A
Explanation: Let N be turned off after x minutes. Then,
Part filled by (M + N) in x min. + Part filled by M in (20 – x) min. = 1
Therefore, x(1/30 + 1/60) + (20 – x) = 1
=> x/20 + (20 - x) = 1
=> 19x = 380
=> x = 20

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Question 10

Time: 00:00:00

The ratio of efficiency of two filling pipes is 5 : 7. There is a third emptying pipe whose efficiency is two thirds of the average efficiency of the first two filling pipes can empty a filled tank in 40 minutes. In how much time both the filling pipes can fill the tank when it is empty?

20/3 minutes

40/3 minutes

45/2 minutes

20 minutes

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Answer: B
Explanation: Let the efficiency of filling pipes is 5x and 7x respectively.
Efficiency of pipe which empty the tank = 2/3 x 12x/2 = 4x
Total work = 4x * 40 = 160
Time to fill the tank by both the pipes = 160x/12x = 40/3 minutes

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