Robert Bosch Profit & Loss Quiz 1

Let him sell x trimax at the gain of 30% and y trimax at a gain of 40%.
Therefore, 0.3x + 0.4y = 0.35(x+y)
0.3x - 0.35x = 0.35y -0.4y
0.05x = 0.5y
x = 10y
Therefore, 10y +y =220 =>y = 20.

The Cost Price (C.P) of 1 dozen bananas = Rs.40.
Hence, the C.P of 5 dozen bananas = 40 x 10 = Rs.400.
Adding Rs.30 towards transportation cost, the total cost price of 10 dozen bananas becomes Rs.430.
Now, the Selling Price (S.P) of 1 dozen bananas = Rs.50.
Hence, the Sales Revenue of 10 dozen bananas = 50 x 10 = Rs.500.
Thus, Net Profit = Sales Revenue - Cost Price = 500 - 430= Rs.70.
The Profit is always expressed as a percentage to cost price. Required answer = (70/430) x 100 = 16.28%.

Explanation:
Let the marked price of the article be Rs. X
Purchase Price (C.P) for priya = 0.70 X.
S.P for priya = (0.70 X) + 25% of (0.70 X) = 990.
0.825 X = Rs.990
=> X = Rs.1200.

Explanation:

Let the cost price for ‘Avartak’ be Rs. X

Therefore, x \times \frac{115}{100} \times \frac{115}{100} = 180440
=>x = 136439 (approx)

Explanation:

C.P. of 25 kg = Rs. (15 × 14.50 + 10 × 13) = Rs. 347.50

S.P. of 25 kg = Rs. (25 × 15) = Rs. 375

∴ Gain = Rs. (375 – 347.50) = Rs. 27.50

Explanation:

Total C.P. = Rs. (12 × 4 + 16 × 2) = Rs. 80

S.P. of 6 dozen oranges = Rs. ( 120/ 100 ×80) = Rs. 96

S.P. per dozen = Rs. 16

Explanation:

Cash price = 95% of 90% of 80% of Rs. 300

= ( 95/100 × 90/100 × 80/100) × 300

= 205.20.

 

Explanation:

Rate of purchase = Rs. 7 per kg.

Rate of selling = Rs. 10 per kg.

To gain Rs. 3, he must purchase = 1 kg.

To gain Rs. 102, he must buy = (1/3 ×102) kg = 34 kg.

Explanation:

C.P.of 65 kg soybean edible oil= Rs. (35 \times 9.50 + 30 \times 10.50) = Rs. 647.50

S.P. of 65 kg soybean edible oil= Rs. 135% of 647.50

S.P. per kg = Rs. \frac{135}{100} \times 647.50 \times\frac{1}{65}
= Rs. 13.44 = Rs. 13.50 approximately.

Let C.P. be Rs. 100. Then, marked price = Rs. 120

S.P. = Rs.\frac{90}{100} \times 120 = Rs. 108

Gain = 8%.