Robert Bosch Averages Quiz-1

Explanation:
Let Gerry Altman
weighs X kg.
According to Gerry Altman , 55 < X < 62
According to Gerry Altman's father, 50 < X < 60
According to Gerry Altman's sister, X < 58
The values satisfying all the above conditions are 56 & 57.
Resultant Average = (\frac{56+57}{2}) = \frac{113}{2}
So, the required average weight of Gerry Altman is 56.5 kg.

Explanation:
Then, the number of construction workers = 9X.
Total number of workers = 9X + X = 10X.
So, Average monthly income,
= \frac{P\times (9X) +Q\times(X)}{10X}
=\frac{X[9P+Q]}{10X}
=\frac{[9P+Q]}{10}

Explanation:
First, We have to find out normal ages of all people:
Grand parents(2 people) = 56 x 2
Parents (2 people) = 27 x 2
Two grandchildren = 7 x 2.
The total people is 6. Then,
Average = \frac{56\times 2+27\times 2+7\times 2}{2+2+2}
= \frac{112+54+14}{6}
= \frac{180}{6}
= 30 Years

Explanation:
Since the month begins with a saturday , So there will be 5 sundays in the month.
Required Average = \frac{430\times5+270\times26}{31}
= \frac{2150+7020}{31}
= \frac{2150+7020}{31}
= 295.80
Rounding off for Approx. Answer = 296 days
Therefore, Number of science enthusiasts per day is 296

Explanation:
Required Average = \frac{18 \times45.55+ 4\times35.25}{18+4}
= \frac{819.9 + 141}{22}
= \frac{960.9}{22}
= 43.67 kgs

Explanation:
If the average of ‘N’ quantities is equal to ‘x’ when a quantity is removed the average becomes ‘y’. Then the value of the removed quantity is [N (x – y) + y].
Given that,
Number of players = N = 27, Difference in average = (x – y) = 1 cm
Old average = x = 162, New average = y = 162 – 1 = 161 cm
By the short trick approach, we get
[N (x – y) + y]
[27 (1) + 161] = [27 + 161] = 188 cm.

Explanation:
If the average of ‘N’ quantities is equal to ‘X’ when a quantity is removed the average becomes ‘Y’. Then the value of the removed quantity is [N (X – Y) + Y].

Given:
Number of persons = N = 15
Old average = X = 15
New average = Y = 14
Difference in average = (X – Y) = 1

By the ShortCut approach, we get
[n (X – Y) + Y]
[15 × (1) + 14] years = 29 years.

Explanation:
Let the number of Walter’s family members be X.
Therefore, the total weight = X.Y
Equation in the 1st situation:
(X + 1) (Y + 1) = XY + 30
XY + X + Y + 1 = XY + 30
X + Y = 29 .....(i)
Equation in the 2nd situation:
(X + 1) (Y - 1) = XY + 18
XY + Y - X - 1 = XY + 18
Y - X = 19 ....(ii)
Solving equations (i) and (ii), we get
2Y = 48, Therefore, Y = 24.

Explanation:
Let the age of Rick, Kevin and Chrissy = A,B and C
A + B = 2 × 20 = 40 yr
B + C = 2 × 19 = 38 yr
C + A = 2 × 21 = 42 yr
On adding all three,
2 (A + B + C) = 40 + 38 + 42 = 120
⇒ A + B + C = 60
∴ A = (A + B + C) – (B + C) = 60 – 38 = 22 yr
Similarly,
B = (A + B) – A = 40 – 22 = 18 yr
C = (C + A) – A = 42 – 22 = 20 yr

Rick’s Age = A = 22 Yrs
Kevin’s Age = B = 18 Yrs
Chrissy’s Age = C = 20 Yrs

Explanation:
Price of StringEnergy Drink in first year = Rs. 7.50 per litre.
∴ Quantity of StringEnergy Drink in first year,
= \frac{4080}{7.50}= 544Litres

Price of StringEnergy Drink in second year = Rs. 8.00 per litre.
∴ Quantity of StringEnergy Drink in second year,
= \frac{4080}{8.00}= 510Litres

Price of StringEnergy Drink in third year = Rs. 8.50 per litre.
∴ Quantity of StringEnergy Drink in third year,
= \frac{4080}{8.50}= 480Litres

Required Average = \frac{3\times 4080}{544+510+480}
= = \frac{12240}{1534}=7.98
=Rs 7.98