Qualcomm Ratio and Proportion Quiz-1

first number:120x/100
second number:150x/100
ratio of two numbers=120x/100:150x/100
=4:5

simply use the shortcut link up the process for finding the ratio.

22     53
25
(53-25) (25-22)
28     3

so the ratio should be 28:3
so 53% strength solvent is 12*3/31
36/31

Assume that the Third Variety of Tea quantity is X.

Then (126*1+135*1+2*x)/(1+1+2)= 153

on solving
261 + 2x = 4x153

2x = 612-261
x=351/2
X= 175.50

5/8*16=10
3/8*16=6
(10+x)/6=3/1
=8

3^2-1=8
4^2+2=18
5^2-1=24
there for
6^2+2=38 ans

If T is speed of train and C is speed of car, then

120/ T + 480/C =8
and
200/T + 400/C = 8+ 20/60 = 25/3 hrs

solving these , we get

C = 80 kmph
and T = 60 km/hr
Ratio of the speed of the train to that of the cars is: 60/80 = 3/4

Let the ratio of maximum marks be 3x : 2x : 5x.
It is given that
their sum is 500. So, 3x + 2x + 5x = 500
10x = 500. => x = 50
So maximum marks of maths, english and hindi are .
3 × 50 = 150 , 2 × 50=100 and 5 × 50 = 250 respectively.
Marks obtained in maths = 50/100 × 150 = 75
Marks obtained in english = 68/100×100 = 68
Overall marks obtained = 73/100 × 500 = 365
Marks obtained in hindi = 365 - (75+68) = 222
Percentage in hindi = 222/250× 100 = 88.8%

If first no is x and other no is y , then

x*40/100 = y*2/3
x/y = 2*100/120 = 200/120 = 5/3

so ratio is 5:3 ...... option c

Dealer gains (300/47)% for a Kg.
Let cost price is Rs100
i.e he gains Rs(300/47) for a Kg
i.e his selling price is Rs(100+300/47)

Now
If he used proper weight then
selling price of Rs100 would account for 1Kg
and selling price of Rs(100+300/47) would account for
1.06382979Kg (approx)

Now
Dishonest 1.06382979Kg is equal to honest 1 Kg
therefore
dishonest 1 Kg is equal to honest (1/1.06382979) Kg
=940 gm approx.