Python Program to count the number of days in a given month of a year
Number of days in a given month of a given year in Python
Here, in this page we will discuss the program to find the number of days in a given month of a given year in python . Number of days in any month of a year can vary specifically in February as the cycle of leap year repeats in every 4 years when the year is leap February gives the count to 29 days but the when the year is not leap it gives count to 28 days and so no of days in a year varies from 365 to 366.
Method Discussed :
- Method 1: Using if-else ladder.
- Method 2 : Using Array
Method 1 :
- Check if the given month is February.
- If True Check if the year is a year leap or not.
- If year is a leap year Print 29 Days, Else Print 28 Days.
- If Condition in Step 3 is False Check the month.
- Print the number of days assigned to specific Month.
Method 1 : Code in Python
Run
month = 12
year=2012
if((month==2) and ((year%4==0) or ((year%100==0) and (year%400==0)))) :
print("Number of days is 29");
elif(month==2) :
print("Number of days is 28");
elif(month==1 or month==3 or month==5 or month==7 or month==8 or month==10 or month==12) :
print("Number of days is 31");
else :
print("Number of days is 30");
Output
Number of days is 31
Method 2 :
In this method instead of using if-else-if ladder or switch case, we use array.
Method 2 : Code in Python
Run
arr = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ]
month = 12
year=2012
if(month==2 and ((year%400==0) or ((year%100!=0) and (year%4==0)))) :
print("Number of days is ", arr[month-1]+1)
else :
print("Number of days is ", arr[month-1]);
Output
Number of days is 31
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arr=[31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ]
m=int(input(“enter a month:”))
y=m-1
b=int(input(“enter a year:”))
if y==1 and (b%400==0) or (b%4==0 and b%100!=0 ):
arr[1]=29
print(f”the number dys in a month are{arr[y]}”)
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list1=[1,2,3,4,5,6,7,8,9,10,11,12]
list2=[31,28,31,30,31,30,31,31,30,31,30,31]
for i in range(0,12):
if month == 2:
if (year % 400 == 0) or (year % 4 == 0 and year % 100 != 0):
print(“29 days “)
break
else:
if list1[i]==month:
print(list2[i],”days”)
def monyear(m,y):
s=str(y)
if(len(s)==4 and m<13):
if(m==2) and (y%4 == 0) or (y%400==0):
noofdays = 29
elif(m==2):
noofdays =28
elif(m==1 or m==3 or m==5 or m==7 or m==8 or m ==10 or m==12 ):
noofdays =31
else:
noofdays =30
return print("no of days are ",noofdays)
else:
print("enter valid year")
monyear(int(input("enter month ")), int(input("enter year ")))
#include
using namespace std;
int main()
{
int Month,Year;
cin>>Month;
cin>>Year;
if(Month == 2 && (Year%4 == 0) || ((Year%100 == 0) && (Year%400 == 0)))
cout<<"Number of days is 29";
//if False check for other conditions
else if(Month == 2)
cout<<"Number of days is 28";
else if(Month == 1 || Month == 3 || Month == 5 || Month == 7 || Month == 8 || Month == 10 || Month == 12)
cout<<"Number of days is 31";
else
cout<<"Number of days is 30";
return 0;
}
//check no. of days in month in C++
#include
using namespace std;
int check_year(int);
int main()
{
int year,month;
cout<>year;
cout<>month;
if(month==2)
{
int result=check_year(year);
if(result==1)
cout<<"29 days";
else
cout<<"28 days";
}
else if(month==1 || month==3 || month==5 || month==7 || month==8 || month==10 || month==12)
cout<<"31 days";
else if(month==4 || month==6 || month==9 || month==11)
cout<<"30 days";
else
cout<<"wrong input";
return 0;
}
int check_year(int year)
{
if(year%4==0 && (year%100!=0 || year%400==0))
return 1;
else
return 0;
}
Java Code :
import java.util.Scanner;
public class Number_of_Days
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.print(“Enter month: “);
int month = sc.nextInt();
System.out.print(“Enter year: “);
int year = sc.nextInt();
sc.close();
if(month==2 && ( (year%4==0 && year%100!=0) || year%400==0) )
System.out.println(“Number of days is 29”);
else if(month == 2)
System.out.println(“Number of days is 28”);
else if(month == 1 || month == 3 || month == 5 || month == 7 || month == 8 ||
month == 10 || month == 12)
System.out.println(“Number of days is 31”);
else
System.out.println(“Number of days is 30”);
}
}
#JAVA_CODE
—————–
package programs;
import java.util.Scanner;
public class NumberOfDaysInaMonth {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.print(“Enter a Month: “);
int mnth=sc.nextInt();
System.out.print(“Enter a Year: “);
int yr=sc.nextInt();
if(mnth == 2 || (yr % 4 == 0) && (yr % 100 == 0 )|| (yr % 400 == 0))
System.out.println(“No of days are 29”);
else if (mnth == 2)
System.out.println(“No of days are 28”);
else if(mnth ==1 || mnth ==3 || mnth ==5 || mnth ==7 || mnth ==8 || mnth ==10 || mnth ==12)
System.out.println(“No of days are 31”);
else
System.out.println(“No of days are 30”);
sc.close();
}
}
program in c language given below:
#include
void main()
{
int year,month;
printf(“enter the year:\t”);
scanf(“%d”,&year);
printf(“enter the month:”);
scanf(“%d”,&month);
if(month==1 || month==3 || month==5 || month==7 || month==8 || month==10 || month==12)
{
printf(“31 days”);
}
else if(month == 2)
{
if(year%4==0)
{
if(year%100==0)
{
if(year%400==0)
{
printf(“29 days”);
}
else{
printf(“28 days”);
}
}
else
{
printf(“29 days”);
}
}
else
{
printf(“28 days”);
}
}
else
{
printf(“30 days”);
}
}
#PROGRAM IN JAVA
import java.util.*;
public class NOofdayINYearMOnth {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.println(“Enter any year: “);
int y=sc.nextInt();
System.out.println(“Enter month: “);
int m=sc.nextInt();
if(m==2)
{
if((y%400==0)||((y%4==0)&&(y%100!=0)))
{
System.out.println(“Number of days is 29”);
}
else
{
System.out.println(“Number of days is 28”);
}
}
else if(m==1||m==3||m==5||m==7||m==8||m==10||m==12)System.out.println(“31”);
else System.out.println(“Number of days is 30”);
}
}
I feel leap year condition is wrong.
Hey Ravi, did you find any input on which the output is coming wrong ??
#PROGRAM IN JAVA
import java.util.*;
public class NOofdayINYearMOnth {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.println(“Enter any year: “);
int y=sc.nextInt();
System.out.println(“Enter month: “);
int m=sc.nextInt();
if(m==2)
{
if((y%400==0)||((y%4==0)&&(y%100!=0)))
{
System.out.println(“Number of days is 29”);
}
else
{
System.out.println(“Number of days is 28”);
}
}
else if(m==1||m==3||m==5||m==7||m==8||m==10||m==12)System.out.println(“Number of days is 31”);
else System.out.println(“Number of days is 30”); } }
Kinda silly ! Everyone keeps writing all the month number apart from using logic
here it should help from python
m=int(input(“Enter month”))
y=int(input(“Enter year:”))
if m==2 and (y%4==0) and (y%100!=0) or (y%400==0):
print(“29 Days”)
elif m==2:
print(“28 Days”)
elif m<=12 and m%2!=0:
print("31 Days")
else:
print("30 Days")