Python Program for Binary To Decimal Conversion
Binary to Decimal Conversion
In this article we will discuss binary to decimal conversion in Python. For this purpose we need to take a binary integer number from user and convert that binary integer number to its decimal equivalent form and then print the converted number on to the screen. A Decimal number can be calculated by multiplying every digits of binary number with 2 to the power of the integers starts from 0 to n-1 where n refers as the total number of digits present in a binary number and finally add all of them.
Working :
A Decimal number can be calculated by multiplying every digits of binary number with 2 to the power of the integers
starts from 0 to n-1 where n refers as the total number of digits present in a binary number and finally add all of them.
Methods Discussed :
- Algorithmic way (Binary to Decimal)
- Inbuilt Method (Binary to Decimal)
Method 1
Algorithm :
- While num is greater then zero
- Store the unit place value of num to a variable (rem)
- Calculate rem with base and add it to answer
- Completely divide Num by 10 and multiply base with 2
Time and Space Complexities
- Time Complexity – O(N), where N is the count of the digits in the binary number
- Space Complexity – O(1), Constant Space
Python Code :
num = 10
binary_val = num
decimal_val = 0
base = 1
while num > 0:
rem = num % 10
decimal_val = decimal_val + rem * base
num = num // 10
base = base * 2
print("Binary Number is {}\nDecimal Number is {}".format(binary_val, decimal_val))
Output :
Binary Number is 10 Decimal Number is 2
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binary=int(input(“enter the number)
decimal=int(binary,2)
print(decimal)
binary=input()
b=binary[::-1]
decimal=0
for i in range(len(binary)):
decimal=decimal+int(b[i])*(2**i)
print(decimal)
def binarytodecimal(n):
d=int(n)
sum=0
p=0
while d>0:
r=d%10
sum=sum+(r*2**p)
d=d//10
p+=1
print(sum)
n=eval(input(‘enter a binary value:’))
binarytodecimal(n)
def get_decimal(binary):
size = len(binary)
decimal = 0
for i in range(size):
decimal += int(binary[(size – i) – 1]) * (2 ** i)
return f”Binary : {binary}\nDecimal : {decimal}”
binary_input = input()
print(get_decimal(binary_input))
num=int(input())
decimal=0
power=0
while num>0:
rem=num%10
decimal+=rem*(2**power)
num=num//10
power+=1
print(decimal)
binary=int(input())
l=len(str(binary))
sum=0
for i in range(l):
sum+=binary%10*pow(2,i)
binary//=10
print(sum)