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Python Program for Binary To Decimal Conversion
Binary to Decimal Conversion
In this article we will discuss binary to decimal conversion in Python. For this purpose we need to take a binary integer number from user and convert that binary integer number to its decimal equivalent form and then print the converted number on to the screen. A Decimal number can be calculated by multiplying every digits of binary number with 2 to the power of the integers starts from 0 to n-1 where n refers as the total number of digits present in a binary number and finally add all of them.
Working :
A Decimal number can be calculated by multiplying every digits of binary number with 2 to the power of the integers
starts from 0 to n-1 where n refers as the total number of digits present in a binary number and finally add all of them.
Methods Discussed :
- Algorithmic way (Binary to Decimal)
- Inbuilt Method (Binary to Decimal)
Method 1
Algorithm :
- While num is greater then zero
- Store the unit place value of num to a variable (rem)
- Calculate rem with base and add it to answer
- Completely divide Num by 10 and multiply base with 2
Time and Space Complexities
- Time Complexity – O(N), where N is the count of the digits in the binary number
- Space Complexity – O(1), Constant Space
Python Code :
num = 10 binary_val = num decimal_val = 0 base = 1 while num > 0: rem = num % 10 decimal_val = decimal_val + rem * base num = num // 10 base = base * 2 print("Binary Number is {}\nDecimal Number is {}".format(binary_val, decimal_val))
Output :
Binary Number is 10 Decimal Number is 2
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bin=’10001′
sum=0
n=len(bin)-1
for i in range(n,-1,-1):
sum=sum+(int(bin[i])*pow(2,i))
print(sum)
ls=[]
for i in str(n):
ls.append(i)
k=len(ls)-1
g=0
i=0
while(i<len(ls)):
if(ls[i]=="1"):
g+=2**k k-=1
i+=1 print(g)
n=input()
s=0
k=len(n)
d=(2**(k-1))
for i in (n):
s=s+(int(i)*d)
k-=1
print(n,”decimal form is”,s)
n=8
print(bin(n)[2:])
n = int(input())
le = len(str(n))
dec = 0
l = le-1
for i in str(n):
dec = dec + (int(i)*(pow(2 , l)))
l = l-1
print(dec)
def binary_to_deci(n):
decimal =0
n1 =str(n)
for i in range(0,len(n1)):
decimal+= (int(n1[i])*pow(2,len(n1)-1-i))
return decimal
n= 1001
print(“Deciaml value of {} is”.format(n),binary_to_deci(n))
n=int(input())
l=list(str(n))
print(l)
l.reverse()
print(l)
decimal=0
for i in range(0,len(l)):
decimal+=int(l[i])*(2**i)
print(decimal)
n=int(input())
ls=[]
for i in str(n):
ls.append(i)
k=len(ls)-1
g=0
i=0
while(i<len(ls)):
if(ls[i]=="1"):
g+=2**k
k-=1
i+=1
print(g)