Python Program to Remove Vowels from a String

June 29, 2023

Program to remove the vowels

The string is built with 2 different types of alphabets grouped as vowels and consonants. In this python program, we will be searching for each alphabet that belongs to the group of vowels and will delete it and print the strings with remaining consonants. As we know String is un-mutable in python so we will initialize a new string and concatenate alphabets that don’t belong to the group of vowels and print it.

Program to remove vowels

We will look at the following methods –

  • Method 1 – Simple iteration on string using for loop
  • Method 2 – Iterate on individual char of string
  • Method 3 – Uses replace method
  • Method 4 – Longer but more clear implementation
  • Method 5 – One line iterator and join method
  • Method 6 – Using regex
  • Method 7 – Using slicing

Method 1

The following method uses
  • A for loop to iterate on the input string
  • Characters are not vowels are added to the result string
Run 
string = "PrepInsta"

vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']
result = ""

for i in range(len(string)):
    if string[i] not in vowels:
        result = result + string[i]

print("\nAfter removing Vowels: ", result)

Output

Enter the String : PrepInsta
After removing Vowels:  Prpnst

Method 2

The following method uses –
  • Iterator to iterate on each character of the input string
  • Unlike the previous method where we use string[i] we directly iterate on char of whole string
Run 
string = "PrepInsta"

vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']
result = ""

for char in string:
    if char not in vowels:
        result = result + char

print("\nAfter removing Vowels: ", result)

Output

After removing Vowels:  Prpnst

Method 3

The following method uses –
  • Creating a copy for Input string called as result
  • Iterate on the whole string char one by one
  • Use an internal replace method that replaces all occurrences of a character in the whole result string
Run 
input_string = "PrepInsta"
result = input_string

vowels = ('a', 'e', 'i', 'o', 'u')

for x in input_string.lower():
    if x in vowels:
        result = result.replace(x, "")

print('After removing vowels : ', result)

Output

After removing vowels :  PrpInst
 
 

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Method 4

This method is a little longer but simple implementation of the same.

Run 
#take user input
String = "PrepInsta"

#initialize new empty string
result = str()
String = String.lower()

for i in String:
    #check condition if alphabet belong to group of vowels
    if i == 'a' or i == 'e' or i == 'i' or i == 'o' or i == 'u':
        pass
    else:
        result = result + i

#check for if the result is not null
if len(result) == 0:
    print('No vowel found in ' + String)
else:
    print('After removing vowels : ' + result)

Output

After removing vowels : prpnst

Method 5

This method uses one line for iterator and join method to join individual list characters.
Run 
def remove_vowel(string):
    vowels = ['a','e','i','o','u']
    
    # result will become : ['P', 'r', 'p', 'n', 's', 't'] after below step
    result = [letter for letter in string if letter.lower() not in vowels]
    
    # result will become Prpnst, i.e. we joined strings in this
    result = ''.join(result)
    print(result)
 
# Driver program
string = "PrepInsta"
print(string)
remove_vowel(string)

Output

PrepInsta
Prpnst

Method 6

The below solution is using regex :-

Run 
# import the module for regular expression (re)
import re
def rem_vowel(string):
    return (re.sub("[aeiouAEIOU]","",string))           

# Driver program
string = "Prepinsta"
print(rem_vowel(string))
Prpnst

Method 7

The following method uses slicing. Advantage we can remove the vowels without needing another variable.
Run 
str = "PrepInsta"

vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']
i = 0
for c in str:
    if c in vowels:
        str = str[:i] + str[i+1:]
        i = i-1
    i = i+1

print("After removing Vowels : ", str)

Output

After removing Vowels :  Prpnst

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11 comments on “Python Program to Remove Vowels from a String”


  • DuttLuri Lalithasri

    s = input(‘enter a input:’)
    t = s
    for i in s:
    if i not in ‘aeiouAEIOU’:
    pass
    else:
    t = t.translate({ord(i):None})
    print(t)

    0

  • Sangram

    a=”
    for i in input(“- “):
    if i in “aeiouAEIOU”:
    pass
    else:
    a+=i
    print(a)

    1

  • NARMADA

    a=str(input())
    b=a.lower()
    a1=str()
    for i in b:
    if (i==’a’ or i==’e’ or i==’i’ or i==’o’ or i==’u’):
    continue
    else:
    a1=a1+i
    print(a1)

    0

  • nidhisingh151199

    s=input()
    l=[“a”,”e”,”i”,”o”,”u”,”A”,”E”,”I”,”O”,”U”]
    l1=[]
    for i in s:
    if(i not in l):
    l1.append(i)
    print(*l1)

    1

  • priyarajswarnakar2018

    a=input()
    l=[‘a’,’e’,’i’,’o’,’u’,’A’,’E’,’I’,’U’,’O’]
    lc=[]
    for i in a:
    if i not in l:
    lc.append(i)
    print(“”.join(lc))

    1

  • Ram

    string=input(“Enter string:”)
    vowels=0
    for i in string:
    if(i==’a’ or i==’e’ or i==’i’ or i==’o’ or i==’u’ or i==’A’ or i==’E’ or i==’I’ or i==’O’ or i==’U’):
    vowels=vowels+1
    print(“Number of vowels are:”)
    print(vowels)

    0

  • Ujjawal

    arr=[‘a’,’e’,’i’,’o’,’u’]
    arr2=[]
    s=str(input())
    for i in s:
    if i not in arr:
    arr2.append(i)
    for i in arr2:
    print(i,end=””)

    0

    • Feel

      You got error in line 5 …How to check string in list frst you change list to str

      0

  • Bibhudutta

    str1=str(input())
    str1=str1.lower()

    for i in str1:
    if(i==’a’or i==’e’ or i==’i’ or i==’o’ or i==’u’):
    continue
    else:
    print(i,end=”)

    1

  • 44_Harsh

    string = str(input(“enter your string”))
    for char in string:
    if char not in “aeiouAEIOU”:
    print(char, end = “”)

    0

  • Souvik

    raw = input()
    res_str = “”

    vowels =[‘a’,’e’,’i’,’o’,’u’,’A’,’E’,’I’,’O’,’U’]

    for ch in raw:
    if ch not in vowels:
    res_str += ch

    print(res_str)

    0