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HSBC Speed and Distance Questions and Answers Quiz-1

Question 1

Time: 00:00:00

Walking at the rate of 4 kmph a man cover certain distance in 2 hr 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in.

12 min

25 min

40 min

60 min

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Solution:
Option(C) is correct

Distance = Speed × time

Here time = 2hr 45 min = 114

hr

Distance = 4×114=11

km

New Speed =16.5 kmph

Therefore time = DS=11/16.5=40 min

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Question 2

Time: 00:00:00

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

None of these

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Solution:
Option(D) is correct

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km =( 9/54)×60

= 10 min

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Question 3

Time: 00:00:00

A train covers a distance in 50 min, if it runs at a speed of 48 kmph on an average. The speed at which the train must run to reduce the time of journey to 40 min will be.

45 kmph

60 kmph

75 kmph

None of thsese

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Solution:
Option(B) is correct

Time = 5060=56

hr

Speed = 48 mph

Distance = S×T=48×(5/6)=40 km

Time = 40/60 hr

New speed = 40×(3/2)=60 kmph

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Question 4

Time: 00:00:00

The jogging track in a sports complex is 726 m in circumference. Suresh and his wife start from the same point and walk in opposite direction at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in:

5.5 minutes

6 minutes

4.9 minutes

5.28 minutes

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Solution:
Option(D) is correct

Let both of them meet after T min

4500 m are covered by Suresh in 60 m.

In T min he will cover 4500T60

Likewise, In T min Suresh's wife will cover 3750T/60

Given,

4500T/60+3750T/60=726

T=5.28 minutes

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Question 5

Time: 00:00:00

A train starts from Delhi at 6:00 am and reaches Ambala cantt. at 10am. The other train starts from Ambala cantt. at 8am and reached Delhi at 11:30 am, If the distance between Delhi and Ambala cantt is 200 km, then at what time did the two trains meet each other?

8:46 am

8:30 am

8:56 am

8:50 am

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Solution:
Option(C) is correct

Average speed of train leaving Delhi = 200/4=50 km/hr

Average speed of train leaving Ambala cantt. = 200×2/7=400/7

By the time the other train starts from Ambala cantt, the first train had travelled 100 km

Therefore, the trains meet after:

=200−100(50+400/7)=1415

hr

=14/15×60=56

minutes

Hence they meet at 8:56 am

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Question 6

Time: 00:00:00

Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 am and travel towards B at 20 km/hr speed. Another train starts from B at 8 am and travel towards A at 25 km/hr speed. At what time will they meet?

9 am

10 am

11 am

None of these

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Solution:
Option(B) is correct

In 1 hour (7 am to 8 am) tarin from station A travels 20 km distance and reaches to C

, (say).

A

----------------- C ---------------B

7 am --------------------------------- 8 am

AC

= 20 km, CB

= 90 km

Distance travelled in 1 hour = 20 km

Remaining distance =110−20

= 90 km

Time=Distance/Speed

9020+25=2 hours

So, time = 8 am + 2 am = 10 am

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Question 7

Time: 00:00:00

A man can row 4.5 km/hr in still water and he finds that it takes him twice as long to row up as to row down the river. Find the rate of the stream.

2 km/hr

2.5 km/hr

1.5 km/hr

1.75 km/hr

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Solution:
Option(C) is correct

Let the speed of the current be x km/hr

Thus upward speed = (4.5−x) km/hr

and downward speed = (4.5+x)

km/hr

Let distance travelled be y, then for the same distance y,

Time Rowing Upwards

=2×Time Rowing Downwards

y/4.5−x=2×y/4.5+x

⇒ x=

1.5 km/hr

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Question 8

Time: 00:00:00

The circumference of the front wheel of a cart is 40 ft long and that of the back wheel is 48 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?

950 ft

1450 ft

1200 ft

800 ft

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Solution:
Option(C) is correct

Let the total distance travelled by the cart be x ft

Then,

x/40−x/48=5

⇒(6x−5x)/240=5

⇒ x

= 1200 ft

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Question 9

Time: 00:00:00

A train 120 m in length passes a pole in 12sec and another train of length 100 m travelling in opposite direction in 10 sec. Find the speed of the second train in km per hour.

43.2 km/hr

43 km/hr

44 km/hr

43.5 km/hr

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Solution:
Option(A) is correct

Let the speed of the train be x

km/hr

Then,

120=x×5/18×12

⇒x=36 km/hr

Let speed of the other train be y km/hr

Then, relative speed in opposite direction:

=(y+36)×518

So total distance:

(120+100)=(y+36)×518×10

y=43.2 km/hr

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Question 10

Time: 00:00:00

A thief steals a car and drives it at 15 km/hr. The theft has been discovered after one hour and the owner of the car sets off in another car at 25 km/hr. When will the owner overtake the thief from the starting point?

1 hr

1.5 hr

2 hr

2.5 hr

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Solution:
Option(B) is correct

Distance covered by the thief in one hour = 15 km

Now this distance is to be covered by the relative speed of (25−15)=10 km/hr

Hence, time required to cover this distance at a speed of 10 km/hr:

=10/15

= 1.5 hr

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