HSBC Logarithms Questions and Answers Quiz-1

none of these

Given, 3-\\frac{1}{2}log_39

=3-\\frac{1}{2}log_33^2

we know, log_ab^n=nlog_ab

=3-\\frac{1}{2}\\times2log_33

we know, log_aa=1

=3-1\\times1

= 2

hence, answer is 2

Currently there is no PrepInsta Explanation. Did you know?

You can also submit your own version of explanations under user explanation section and also view other submitted explanations by other users.

Logx= log 3 + 2 log 2- (3/4) log 16.

= log3+log4- log 16^3/4

=log3+log4-log2^12/4

=log3+log4-log2³

=log(3*4/8)

=log(3/2)

Logx=log3/2

x=3/2

Log[(a+b)/3] = 0.5[log(a) + log(b)]
log[(a+b)/3] = 0.5*log(ab)
log[(a+b)/3] = log[sqrt(ab)]
(a+b)/3 = sqrt(ab)
a + b = 3*sqrt(ab)
a^2 + 2ab + b^2 = 9 ab
a^2 + b^2 = 7ab

log10(1/70)=log10 1- log 10 70
= 0-log10 (10*7)
=-((log10 10 )+(log10 7))
=- (1+a)

xy = x + y

xy - y = x

y (x - 1) = x

y = x / (x - 1)

Let log be log to base 8
log [ x/6 ] = 1/3
x/6 = 8^(1/3)
x/6 = 2
x = 12

log(a) / log(b) = y/x

1000