Logical Reasoning Quiz-1B

The arrangement of the persons is
Q W M V N U S O T P R
U is sitting in the center of the row.

The arrangement of the persons is
Q W M V N U S O T P R
OTPR are sitting to the right of S.

The arrangement of the persons is
Q W M V N U S O T P R
Hence N is sitting between V and U.

The arrangement of the persons is
Q W M V N U S O T P R
O and P are the immediate neighbours of T.

The arrangement of the persons is
Q W M V N U S O T P R
If the persons as given in the question change their positions then we have the arrangement P R T V O U S N M Q W
Hence P and W are sitting at the ends.

We are given that 15th March 1816 was a Friday.
Now we know that 100 years have 5 odd days. So till 15th March 1916, we will be having 5 odd days. So if we move from 15th March 1816 to 15th March 1916, we will encounter 5 odd days.
Now from 15th March 1916 to 15th April 1916 there would be 3 odd days.
So total number of odd days = 5+3 =8
8 mod 7 = 1
So 15th April 1916 would be Friday + 1= Saturday

Since it has been mentioned that Mohan was not born in February, so he can’t be born on 29th Feb. Hence He will celebrate his next birthday on a Wednesday in the year for which the sum of the odd days becomes 5 or a multiple of 5.
By his birthday in 2017, there will be 1 odd day.
By his birthday in 2018, there will be 2 odd days.
By his birthday in 2019, there will be 3 odd days.
By his birthday in 2020, there will be 5 odd days, as 2020 is a leap year.
So in 2020 He will celebrate his birthday on Wednesday.

30 years. The number of leap years is 8 (1972,1976,1980,1984,1988,1992,1996,2000).

So, the total number of days = 22*365 + 8*366 = 10958

10958 mod 7 = 3

Since 9/12/2001 is a Sunday, 9/12/1971 should be a Thursday.

Since the watch has to show correct time as 9, when it looses 12 hours.
Time taken to lose 5 minutes = 1 hour.
Time taken to lose 12 hours = 12*60/5 = 144 hours = 6days
Starting from Wednesday, after 6 days it would be Tuesday 7th September.
After Tuesday 7th September, Monday (13 th September) would occur after further 6 days.

Speed of X = 50/5 = 10 m/s
Speed of Y = 40/5 = 8 m/s
Time taken by Y to finish the race = 50/8 = 6.25 s
It is now known that the faulty clock lost time and has shown 6s instead of 6.25s for Y.
Similarly the time taken by Z = 3 * 6.25/6 = 3.125s
Speed of Z = 50/3.125 = 16 m/s.