Command Line program to find Armstrong number using Command line arguments

Armstrong Number Command Line Programming

#include<stdio.h>
#include<stdlib.h>

int main(int argc,char *argv[])
{
int Given_number= atoi(argv[1]);
int num;
for(num=1; num<=Given_number; num++)
{
int a=num;
int s=0;
int r=0;

while(a>0)
{
s=a%10;
r=r+(s*s*s);
a=a/10;
}
if(r==num)
printf(” %d isarmstrong no \n”, num);
}
}

[/code]

Code – 2

[code language=”cpp”]

#include<stdio.h>

void main(int argc, char * argv[])

{

int num,num1,arms=0,rem;

if ( argc != 2 )

{

printf(“Enter the number:\n”);

scanf(“%d”,&num);

}

else

{

num = atoi(argv[1]);

}

num1=num;

while(num>0)

{

rem=num%10;

arms=arms+rem*rem*rem;

num=num/10;

}

if(num1==arms)

{

printf(” \n%d is an Armstrong number”,num1);

}

else

{

printf(“\n%d is NOT an Armstrong number”,num1);

}

}

[/code]