C++ Program for Octal to Binary conversion
Octal to Binary Conversion
There are 2 approaches of converting an octal number into a binary number like:
- Write 3 digit binary number for all the digits of a number from left to right.
- first convert octal to decimal and then decimal to binary .
We are using the second approach, it is a long but very simple approach which can also be implemented easily with minimum chances of error.
Method 1:-
- Accept octal number
- Convert it into decimal Equivalent
- Convert this decimal value into Binary
Make sure you have visited these two pages before moving ahead with the code –
Method 1 Code in C++
Run
// this program converts octal to binary
// by converting octal->decimal->binary
#include<iostream>
#include<math.h>
using namespace std;
void
convert (int octal)
{
int i = 0, decimal = 0;
//converting octal to decimal
while (octal != 0)
{
int digit = octal % 10;
decimal += digit * pow (8, i);
octal /= 10;
i++;
}
printf ("Decimal Value: %d\n", decimal);
long long binary = 0;
int rem;
i = 1;
// converting decimal to binary here
while (decimal != 0)
{
rem = decimal % 2;
decimal /= 2;
binary += rem * i;
// moving to next position ex: units -> tens
i *= 10;
}
cout << binary;
}
int
main ()
{
int octal;
cout << "Octal Value: "; cin >> octal;
convert (octal);
return 0;
}
Output
Octal Value: 12
Decimal Value: 10
Binary Value: 1010
Method 2
Each digit of an octal number can be converted into its binary Equivalent (see image)
Binary Representation for Octal digit:
- 0 => 000
- 1 => 001
- 2 => 010
- 3 => 011
- 4 => 100
- 5 => 101
- 6 => 110
- 7 => 111
Method 2 Code in C++
Run
#include<iostream>
#define MAX 1000
using namespace std;
void
convert (char octalnum[])
{
int i = 0;
cout << "Equivalent Binary Number: ";
while (octalnum[i])
{
//use switch case for multiple condition
switch (octalnum[i])
{
case '0':
printf ("000");
break;
case '1':
printf ("001");
break;
case '2':
printf ("010");
break;
case '3':
printf ("011");
break;
case '4':
printf ("100");
break;
case '5':
printf ("101");
break;
case '6':
printf ("110");
break;
case '7':
printf ("111");
break;
//for invalid case
default:
cout << "\n Invalid octal digit %c " << octalnum[i];
return;
}
i++;
}
return;
}
int
main ()
{
char octalnum[MAX];
cout << "Insert an octal number: ";
cin >> octalnum;
convert (octalnum);
}
Output
Insert an octal number: 347
Equivalent Binary Number: 011100111
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