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C++ program for Converting digit/number to words
Converting digit/number to words in C++
Here, in this page we will discuss the program for Digit/number to words in C++ .The conversion of numbers in words is just a conversion of numeric values to the English format of reading numbers. This code supports the conversion of numbers from 0 – 9999 in English format. Digits have different places when read from its ones place to above. Different places for numbers are:-
- Single digits:- Ones
- Two Digits:-Tens
- Three Digits:- Hundreds
- Four Digits:- Thousands
Algorithm
- Taking input as a string from the user.
- Check the length of the input.
- if the length is zero print ’empty’ and if the length is greater than 4 print ‘give a string of specific length’
- if length id between 1 – 4, Create arrays for different values.
- Checking the length of the string.
- According to the place of the digit, we will show the output.
C++ Code:-
//C++ program
//convert number to text
#include<bits/stdc++.h>
using namespace std;
//main Program
void numToWords(string num)
{
int length_of_string = strlen(num);
if (length_of_string == 0){
cout<<"String is Empty";
return;
}
if (length_of_string > 4){
cout<<"Please enter the string with supported length";
return;
}
string ones_digits = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
string tens_digits = {"", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen","nineteen"};
string multiple_of_ten = {"", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"};
string power_of_ten = {"hundred", "thousand"};
cout<<num<<":\n";
if (length_of_string == 1){
cout<<ones_digits[num[0] - '0'];
return;
}
int x=0;
while (x < strlen(num)){
if(length_of_string >= 3){
if (num[x] - 48 != 0){
cout<<ones_digits[num[x] - 48]<<"\n";
cout<<power_of_ten[length_of_string - 3]<<"\n";
length_of_string--;
}
}
else{
if (num[x] - 48 == 1){
sum = (num[x] - 48 + num[x] - 48);
cout<<tens_digits[sum]);
return;
}
else if(num[x] - 48 == 2 and num[x + 1] - 48 == 0){
cout<<"twenty";
return;
}
else{
int i = num[x] - 48;
if(i > 0){
print(multiple_of_ten[i], end = " ");
}
else{
print("", end = "");
}
x += 1;
if(num[x] - 48 != 0){
cout<<ones_digits[num[x] - 48];
}
}
}
x++;
}
}
int main()
{
numToWords("1121");
return 0;
}
Output:
1121 : one thousand one hundred twenty one
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