C program to remove brackets from an algebraic expression

October 14, 2022

Removing brackets from an algebraic expression.

In this article we will learn how to code a C program to remove brackets from an algebraic expression. We will be using a while loop that will iterate each character till the end of the string , and store the string in new character array . If brackets are found then we will skip them and as the iteration ends we will get an algebraic expression without brackets. 

C program to remove brackets from an algebraic expression

Algorithm:

  • Initialize the variables.
  • Accept the input.
  • Initialize a while loop and terminate it at the end of string. 
  • Iterate each character of the string through that loop.
  • Store these characters into an new array skip brackets , if found.
  •  Print result.

 

While loop in C

C programming code to remove brackets from an algebraic expression

#include<stdio.h>  
int main()
{
    //Initializing variables.
    char str[100] = "Prep))insta", str_no_spc[100];
    int i=0, j=0 ;
    
    //Iterating each character of string.
    while(str[i] != '\0')
    {
        if(str[i] != '(' &&  str[i] != ')')//Excluding brackets.
        {
            str_no_spc[j++] = str[i];
        }
        i++;
    }
    str_no_spc[j] = '\0';
    
    //Printing result.
    printf("The string after removing all the spaces is:\n%s", str_no_spc);
    return 0;
}

Output

The string after removing all the spaces is:
Prepinsta

Method 2

Here we are using the same concept as above but this is implemented using for loop.

#include<stdio.h>   
int main() {
     //Initializing variables.
    char str[100] = "P(r(e)p)Ins)ta", str_no_spc[100];
    int i = 0, j = 0 ;
       
    //Iterating each character of string.
    for (int i = 0; str[i] != '\0'; i++)
    {
       if (str[i] != '(' &&  str[i] != ')')  // Excluding brackets.
        {
              str_no_spc[j++] = str[i];
        }
    }

    str_no_spc[j] = '\0';
    //Printing result.
    printf("The string after removing all the spaces is:%s", str_no_spc);
       return 0;
}

Output

The string after removing all the spaces is:
PrepInsta
 
 

Toggle each character in a string

Count the number of vowels

Length of the string without using strlen() function

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While loop in C

5 comments on “C program to remove brackets from an algebraic expression”


  • Syeda

    Python Code:
    exp = input()
    res = ”
    for i in exp:
    if(i=='(‘ or i==’)’ or i=='{‘ or i==’}’):
    pass
    else:
    res+=i
    print(res)


  • Geetha

    #python code
    n=input()
    A=[]
    for i in n:
    if i=='(‘ or i==’)’:
    pass
    else:
    A.append(i)
    print(*A,sep=”)


  • Prathamesh

    #IN Python:
    string=input()
    string2=’ ‘
    for i in string:
    if(ord(i) == 40 or ord(i) ==41) :
    pass
    else:
    string2+=I
    print(string2)


  • Shaik

    s=list(input(‘enter the string ‘))
    for i in s:
    if i==”(” or i==”)”:
    s.remove(i)
    print(”.join(s))


  • kandukuri

    #include
    #include
    void main()
    {
    int i, j;
    char str[100];
    printf(“enter the string you want:”);
    gets(str);
    for (i = 0; str[i] != 0; i++)
    {
    while (str[i] == ‘(‘ || str[i] == ‘)’)
    {
    for (j = i; str[j] != 0; j++)
    {
    str[j] = str[j + 1];
    }
    str[j] = ‘\0’;
    }
    }
    printf(“the string is new one is %s”, str);
    }