Replace All 0’s With 1 In A Given Integer | C Program
Program to Replace all 0’s with 1 in a given integer
Here we will discuss how to replace all the 0’s with 1 in a given integer using C programming language.
The concept is simple, find the digits of the integer. Compare each digit with 0 if the digit is equal to 0 then replace it with 1. Construct the new integer with the replaced digits.
The program for Implement a C Program to replace all 0’s with 1 in a given integer as an input, all the 0’s in the number has to be replaced with 1.
Question can come like Way 1
Write a code to change all zero's as one's (0s as 1s) in a given number? ex: 120014 needs to be printed as 121114
Question can come like Way 2
implement a c program to replace all 0's with 1 in a given integer as an input, all the 0's in the number has to be replaced with 1.
Algorithm
- Take Input in num and initialize a variable num with with value 0
- If num is equals to zero then update the value of num2 to 1
- Iterate using a while loop until num is greater then 0
- For each iteration initialize a variable rem and store unit digit of num
- If rem equals to 0 then set rem to 1
- Set num to num divide by 10 & num2 equals to num2*10+rem
- Reverse and print num2
C code
Run
#include<stdio.h>
//main program
int main()
{
int num,num2=0;
printf("Enter number: ");
//user input
scanf("%d", &num);
//checking for 0 input
if(num == 0)
num2=1;
//converting 0 to 1
while(num>0)
{
int rem = num%10;
if(rem == 0)
rem = 1;
num = num/10;
num2=num2*10+rem;
}
num = 0 ; // Store the reverse of num2
while(num2>0){
int r = num2%10;
num= num*10 + r;
num2 /= 10;
}
//converted number
printf("Converted number is: %d" ,num);
return 0;
}
Output
Enter number: 900120678 Converted number is: 911121678
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#include
int main()
{
int s,base=1,sum=0,n;
scanf(“%d”,&n);
while(n>0){
s=n%10;
if(s==0)
{
s=1;
}
n=n/10;
sum=sum+s*base;
base*=10;
}
printf(“%d”, sum); }
#include
int main()
{
int s,base=1,sum=0,n;
scanf(“%d”,&n);
while(n>0){
s=n%10;
if(s==0)
{
s=1;
}
n=n/10;
sum=sum+s*base;
base*=10;
}
printf(“%d”,sum);
}
#Solution in Python
def replace_0(num):
temp = ”
for i in str(num):
i = str(i)
if i == ‘0’:
temp += ‘1’
else:
temp += i
return int(temp)
Code complexity:
O(n) Time, O(n) space
#include
int main() {
int n,r,d=0,i=1;
scanf(“%d”,&n);
if(n==0)
printf (“1”);
else
while (n>0)
{
r=n%10;
if(r==0)
{
r=1;
}
d=d+r*i;
n=n/10;
i=i*10;
}
printf (“%d”,d);
return 0;
}