# C Program for finding the occurrence of a digit in a given number ## Occurrence of a Digit in a given Number in C

Here, in this page we will discuss the program to find the occurrence of a digit in a given number in C .The input may lie within the range of integer.

If the digit does not occur in the input it should print 0 else the count of digits.

## Algorithm

• Declare variable count that will count the required number of occurrences
• Take a while loop.
• Declare a variable rem to store every digit of the number to be compared.
• Compare rem with the digit
• if rem equals digit increment count.
• n=n/10
• Print the value of count.

We will implements the above algorithm using two methods,

• Method 1 : Iterative way
• Method 2 : Recursive way.

### Method 1 : Code in C

```Run
//Write a program to print the Occurrence of a Digit in a given Number in C
#include<stdio.h>

int main() {

int n = 890190798;
int d = 9;

int count=0;

while(n) {

int rem = n%10;
if(rem == d){
count++;
}
n=n/10;
}

printf("%d",count);

return 0;

}

```

`3`

### Method 2 : Code in C

Run
```//Write a program to print the Occurrence of a Digit in a given Number in C
#include <stdio.h>

int count(int n, int d){
if(n<=0)
return 0;

int rem = n%10;

if(rem == d){
return 1 + count(n/10, d);
}

return count(n/10, d);
}
int main() {

int n = 890190798;
int d = 9;

int x = count(n, d);
printf("%d",x);

return 0;

}

```

`3`

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