Convert Digit/Number To Words

September 30, 2022

Write a C program to find Convert digit/number to words :-

In C programming, converting Digit/number to words requires a specific program. In this, the user is required to insert an integer number which is yet again changed and shown in terms of words with the help of code implementation. The code takes numbers up-to 4 digits, that is, numbers from 0 to 9999. The concept is to make array s that store separate parts of output strings. One array is intended for single numbers, one for figures from 10 to 19, one for 20, 30, 40, 50, etc, as well as one for powers of 10.

Algorithm :

Get the number from the user smaller than four digits.
If the length is less than 0, print “The String is Empty”.
Run the while loop until the number is not equal to zero.
Check while the number is less than zero and equal to three, the numbers divided and their corresponding words are written.
Repeat step 5 until length of the string reaches zero.
If length =1, print the words for the single digit.
Check conditions if the number lies between 22 and 99 and print the corresponding word.

C program:-

Run

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void convert_to_words(char* num)
{
    int len = strlen(num);
 
    /* Base cases */
    if (len == 0) {
        fprintf(stderr, "empty string\n");
        return;
    }
    if (len > 4) {
        fprintf(stderr,
                "Length more than 4 is not supported\n");
        return;
    }
 
    char* single_digits[] = { "zero", "one", "two",   "three", "four", "five", "six", "seven", "eight", "nine" };
 
    char* two_digits[]= { "", "ten", "eleven","twelve", "thirteen",  "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };
 
    char* tens_multiple[] = { "", "", "twenty", "thirty", "forty",   "fifty", "sixty",  "seventy", "eighty", "ninety" };
 
    char* tens_power[] = { "hundred", "thousand" };
 
    printf("\n%s: ", num);
 
    if (len == 1) {
        printf("%s\n", single_digits[*num - '0']);
        return;
    }
 
    while (*num != '\0') {
 
        if (len >= 3) {
            if (*num - '0' != 0) {
                printf("%s ", single_digits[*num - '0']);
                printf("%s ", tens_power[len - 3]); 
            }
            --len;
        }
 
        else {
            if (*num == '1') {
                int sum = *num - '0' + *(num + 1) - '0';
                printf("%s\n", two_digits[sum]);
                return;
            }
 
            else if (*num == '2' && *(num + 1) == '0') {
                printf("twenty\n");
                return;
            }
 
            else {
                int i = *num - '0';
                printf("%s ", i ? tens_multiple[i] : "");
                ++num;
                if (*num != '0')
                    printf("%s ",
                           single_digits[*num - '0']);
            }
        }
        ++num;
    }
}
 
int main(void)
{
    convert_to_words("9459");
    return 0;
}

Output

9459 : nine thousand four hundred fifty nine

Can a number be expressed as a sum of two prime numbers

Count possible decoding of a given digit sequence

Find the prime numbers between 1 to 100

Calculate the number of digits in an integer

Counting number of days in a given month of a year

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