Aricent Directional Sense Quiz-1

The movements of Radha are shown in fig.

Clearly Radha's distance from starting point O

= OD = ( OC - CD ) = (AB - CD)

= ( 14 - 4 ) m = 10m

Clearly,

Gaurav's distance from his initial position P = PX = (PS + SX )

= (QR + SX) = ( 40 + 20 ) m = 60 m

The man initially faces in the direction OP. On moving 90° clockwise he faces in the direction OX. On further moving 180° anticlockwise he faces in the direction OY, finally on moving 90° anticlockwise he faces in the direction OZ which is south-east.

The movements of the person are from A to F, as shown in figure. Clearly, the final position is F which is to the North-east of the starting point A

it is finally walking in the direction FG.i.e., North.

The movement of sachin are as shown in fig( P to B, B to C, C to D, and D to Q ).Clearly, distance of Q from P = PQ = (DQ - PD) = (DQ - BC) = (40 - 30 ) m = 10 m. Also Q is the West of P.

The movements of Rohan are as shown in fig( A to B, B to C, C to D and D to E). Clearly, AD = BC = 2km.So, required distance = AE. = (DE - AD) = (3 - 2) km = 1 km.

Sun rises in the east in the morning. Since the shadow of Suresh falls to his right. So he is facing South.

At 9.15 P.M., the minute hand will point towards west.

West will become South-East.