Aricent Profit and Loss Quiz-1

C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.

S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.

Gain =(80/1600*100) % = 5%

Let S.P. of 45 lemons be Rs. x.



Then, 80 : 40 = 120 : x or x = 40×12080= 60



For Rs.60, lemons sold = 45



For Rs.24, lemons sold =4560×24= 18.

Gain % = ((100+common gain %)2100−100)%



=((100+10)2100−100)


= 21%

Let the cost price of 1-liter pure milk be Re.1, then

{6 liters (milk) → C.P = Rs. 62 liters (water) → C.P = Rs. 0→CP = Rs.6 only


8 litre mixture =>

SP => 8 x 2 = Rs. 16



Profit % = 16 − 66x100 = 10006 = 166.66%

Let the C.P be Rs.100 and S.P be Rs.x, Then
The profit is (x-100)
Now the S.P is doubled, then the new S.P is 2x
New profit is (2x-100)
Now as per the given condition;
=> 3(x-100) = 2x-100
By solving, we get
x = 200
Then the Profit percent = (200-100)/100 = 100
Hence the profit percentage is 100%

Video solution:

Let C.P. be Rs. x.



Then,= >1920−xx*100=x−1280x*100


=> 1920 - x = x - 1280



=> 2x = 3200



=> x = 1600



Required S.P. = 125% of Rs. 1600 =Rs(125/100*1600) = Rs2000

Least Cost Price = Rs. (200 * 8) = Rs. 1600.

Greatest Selling Price = Rs. (425 * 8) = Rs. 3400.

Required profit = Rs. (3400 - 1600) = Rs. 1800.

Video solution:

Cost Price = Rs.[100125×8750] = Rs. 7000. Let the labelled price be Rs. x.



Then, 70100*x=7000 ⇒x=Rs.(7000*10070)



= Rs.10000

Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.

S.P. of x articles = Rs. 20.

Profit = Rs. (20 - x).

(20−xx*100=25)

=> 2000 - 100x = 25x

=> 125x=2000

=> x=16

Video solution:

Let original Cost price is x
Its Selling price = (105/100) * x = 21x/20
New Cost price = (95/100) * x = 19x/20
New Selling price = (110/100 )* (19x/20 )= 209x/200
[(21x/20) - (209x/200)] = 1
=> x = 200

Video solution: