Dynamic Memory Allocation in C using Realloc
Dynamic memory allocation using realloc :
On this page we will discuss about dynamic memory allocation using realloc. Realloc function is also know as reallocation. As the name suggests realloc function is use to re-allocate the data from old memory block to new memory block. Basically realloc function is used to add more memory to the previously allocated memory block.
Dynamic memory allocation using realloc function
Realloc( ) function is used to change the size of the memory block without losing the old data.It is a built in function declared in stdlib.h .As the name itself suggests realloc( ) means reallocation.
Syntax:
void*realloc(void*ptr, newsize);
As we can see from the synatx realloc( ) will return a void pointer.Apart from this,It requires two arguments.The first is a pointer to the previously allocated memory and the another one is new size.On failure, realloc( ) returns NULL pointer.
Example:
int *ptr=(int*)malloc(sizeof(int)); ptr=(int*)realloc(ptr,2*sizeof(int));
In the above example, let’s say we have malloc( ) function which allocates memory for one integer. If we use the realloc( ) function in this case the pointr to the previously allocated memory is required and second argument is new size.
Some more Information:
- This will allocate memory space of 2*sizeof(int) (i.e twice of what previously allocated)
- Also this function moves the content of old block to a new memory block and the data of old block is not lost.
- We may lose the data when the new size is smaller than the old size.
- The bytes which are allocated newly by realloc function will not get initialized.
Programming Example of realloc :
#include <stdio.h>
#include <stdlib.h>
int main ()
{
int *ptr;
int a, j;
a = 6; //number of elements
ptr = (int *) calloc (a, sizeof (int)); //run time allocation
if (ptr == NULL)
{
printf ("Memory not allocated.\n");
exit (0);
}
else
{
printf ("Memory successfully allocated using calloc.\n");
for (j = 0; j < a; ++j)
{
ptr[j] = j + 1;
}
printf ("The elements of the array are: ");
for (j = 0; j < a; ++j)
{
printf ("%d, ", ptr[j]);
}
a = 12; //new size
ptr = realloc (ptr, a * sizeof (int)); //reallocation using realloc()
printf ("\nMemory successfully re-allocated using realloc.\n");
for (j = 5; j < a; ++j)
{
ptr[j] = j + 1;
}
printf ("The elements of the array are: ");
for (j = 0; j < a; ++j)
{
printf ("%d, ", ptr[j]);
}
free (ptr); //deallocate the pointer
}
return 0;
}
Output:
Memory successfully allocated using calloc. The elements of the array are: 1, 2, 3, 4, 5, 6, Memory successfully re-allocated using realloc. The elements of the array are: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
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