Python program to find non repeating characters in a string
Find Non Repeating Characters
The string is a combination of characters when 2 or more characters join together it forms string whether the formation gives a meaningful or meaningless output. In python programming, we treat a single character also as a string because there is no datatype as a character in python. In this python program, we will find unique elements or non repeating elements of the string.
Algorithm
- Step 1:- store the string in a varaible lets say String.
- Step 2:- lets it be “prepinsta”.
- Step 3:- Start iterating through string.
- Step 4:- Initialize count variable.
- Step 5:- Again start iterating through same string.
- Step 6:- Increment count variable as character is found in string.
- Step 7:- If count is more then 2 break the loop.
- Step 8:- If count is 1 print the character.
- Step 9:- End.
Python Code:- Find Non Repeating Characters
#take user input
String = "prepinsta"
for i in String:
#initialize a count variable
count = 0
for j in String:
#check for repeated characters
if i == j:
count+=1
#if character is found more than 1 time
#brerak the loop
if count > 1:
break
#print for nonrepeating characters
if count == 1:
print(i,end = " ")
Output
r e i n s t a
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def non_repeat_chr(str1):
l =””
for i in str1:
if str1.count(i)==1:
l+= i
print(f” non-repeating char : {“,”.join(l)}”)
str1 =input(“enter a string: “)
non_repeat_chr(str1)
String = “Ashutosh”
b = list(dict.fromkeys(String)) # This method is used to remove the duplicate
print(b)
Kindly refer to our discord community for all your technical doubts.
string = “prepinsta”
for i in string:
frequency = string.count(i)
if(frequency==1):
print(str(i),end=”,”)
s = input(‘enter a value:’)
for i in s:
if s.count(i)<2:
print(i)
s = input(‘enter a value:’)
t = []
for i in s:
if s.count(i)<2:
t.append(i)
print(t)
a=input(“-> “)
ls=[i for i in a if a.count(i)==1]
print(ls)
#simple loop
a=input()
for i in a:
if(a.count(i)==1):
print(i,end=””)
#using set concept
a=input()
b=set(a)
for i in b:
if(a.count(i)<2):
print(i,end=" ")
else:
pass
string1=”prepinsta”
string2=””
for i in string1:
if string1.count(i)>1:
pass
else:
string2=string2+i
print(string2)