Wells Fargo Time, Speed and Distance Problems with Solutions Quiz-1

Answer: Option A
Solution:
Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 – 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.

Answer: Option D
Solution:
Speed = 200/24 m/sec = (200/24 x 18/5)Km/hr = 30 km/hr

Answer: Option A
Solution:
1 man’s 1 day work = 1/48; 1 woman’s 1 day work = 1/60.
6 men’s 2 day’s work = 6/48 * 2 = 1/4.
Remaining work = (1 – 1/4) = 3/4
Now, 1/60 work is done in 1 day by 1 woman.
So, 3/4 work will be done in 3 days by (60 * 3/4 * 1/3) = 15 women.

Answer: Option B

Explanation:

Initial speed = 80km/hr
Total distance = 80 * 10 = 800km
new speed = 800/4 =200km/hr
Increase in speed = 200 - 80 = 120km/hr

Explanation:

Difference between speeds of car A and car B = 60/3 = 20km/hr
But from the result it is impossible to find the speed of car A because here the unkowns are two (Speeds of cars A and B ) but the equation is only one.

Solution : We are given that the first runner can complete a 750 m race in 2 minutes and 30 seconds or 150 seconds.

=> Speed of the first runner = 750 / 150 = 5 m / sec

We convert this speed to km / hr by multiplying it by 18/5.

=> Speed of the first runner = 18 km / hr

Also, we are given that the speed of the second runner is 17.95 km / hr.

Therefore, the first runner can beat the second runner.

Solution : We are given that two thirds of the 6 km was covered at 4 km / hr.

=> 4 km distance was covered at 4 km / hr.

=> Time taken to cover 4 km = 4 km / 4 km / hr = 1 hr = 60 minutes

=> Time left = 84 – 60 = 24 minutes

Now, the man has to cover remaining 2 km in 24 minutes or 24 / 60 = 0.4 hours

=> Speed required for remaining 2 km = 2 km / 0.4 hr = 5 km / hr

Solution : Let time taken by postman to travel from post office to village=t minutes.

According to the given situation, distance from post office to village, say d1=25/60*t km {25 km/hr = 25/60 km/minutes}

And

distance from village to post office, say d2=4/60*(174-t) km {2 hours 54 minutes = 174 minutes}

Since distance between village and post office will always remain same i.e. d1 = d2

=> 25/60*t = 4/60*(174-t) => t = 24 minutes.

=> Distance between post office and village = speed*time =>25/60*24 = 10km

Solution : Let the distance between his home and the station be ‘d’ km.

=> Time required to reach the station at 5 km / hr = d/5 hours

=> Time required to reach the station at 6 km / hr = d/6 hours

Now, the difference between these times is 12 minutes = 0.2 hours. (7 minutes late – 5 minutes early = (7) – (-5) = 12 minutes)

Therefore, (d / 5) – (d / 6) = 0.2

=> d / 30 = 0.2

=> d = 6

Thus, the distance between his home and the station is 6 km.