Find the “Kth” max and min element of an array

6 comments on “Find the “Kth” max and min element of an array”

• 
  

  nandan767644

  def kth_min_max(arr, k):
  arr.sort()
  kth_min = arr[k – 1]
  kth_max = arr[-k]
  return kth_min, kth_max

  # Example
  arr = [7, 10, 4, 3, 20, 15]
  k = 3
  kmin, kmax = kth_min_max(arr, k)
  print(“Kth smallest:”, kmin)
  print(“Kth largest:”, kmax)

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• 
  

  rohitraj4513

  #Find the “Kth” max and min element of an array
  arr = [ 2 , 4 , 18 , 77 , 22 , -89 , 18 , 88 , 336]
  low = 10**9
  mx = -10**9
  for i in range(len(arr)):
  if arr[i] mx :
  mx = arr[i]
  print(f”Max element in Array : {mx}”)
  print(f”min element in Array : {low}”)

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• 
  

  Mathavan SG

  k=int(input(‘enter k value’))
  a=list(map(int,input().split()))
  n=len(a)
  def findkmax(k,a):
  for i in range(n):
  for j in range(0,n-1-i):
  if a[j]a[j+1]:
  a[j],a[j+1]=a[j+1],a[j]
  print(a)
  print(‘kin element’,a[k-1])

  findkmax(k,a)
  findkmin(k,a)

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• 
  

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• 
  

  Prayansh

  l=[10,56,20,48,21,458,-1,0,569]
  n=len(l)
  while True:
  k=int(input(“Enter k: “))
  if k<=n:
  break
  else:
  print("Wrong value enter again: ")

  l1=sorted(l)
  min=l1[k-1]
  max=l1[n-k]

  print(min,max)

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• 
  

  nitesh

  def minman(arr,k):
  arr.sort()
  max=arr[-k]
  min=arr[k-1]
  return min,max

  arr=[1,25,38,43,54,68,72,28,19,12]
  k=2
  s,d=minman(arr,3)
  print(s)
  print(d)

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