JAVA Program for Coin Distribution Problem

December 29, 2021

Coin Distribution Problem

Coin Distribution Problem is one of the questions that was asked in previous year TCS CodeVita Coding Competition. It is a simple combination and permutation problem which can be solved using if – else condition. Let’s see how we can code a Java Program for Coin Distribution Problem. You can practice all the other coding question on our TCS CodeVita Coding Questions Page

Problem Statement

Find the minimum number of coins required to form any value between 1 to N,both inclusive.Cumulative value of coins should not exceed N. Coin denominations are 1 Rupee, 2 Rupee and 5 Rupee.Let’s Understand the problem using the following example. Consider the value of N is 13, then the minimum number of coins required to formulate any value between 1 and 13, is 6. One 5 Rupee, three 2 Rupee and two 1 Rupee coins are required to realize any value between 1 and 13. Hence this is the answer.However, if one takes two 5 Rupee coins, one 2 rupee coin and two 1 rupee coin, then too all values between 1 and 13 are achieved. But since the cumulative value of all coins equals 14, i.e., exceeds 13, this is not the answer.

Input Format:
- A single integer value.

Output Format:
- Four space separated integer values.
  - 1st – Total number of coins.
  - 2nd – number of 5 Rupee coins.
  - 3rd – number of 2 Rupee coins.
  - 4th – number of 1 Rupee coins.

Constraints:
- 0 < n < 1000

Refer the sample output for formatting

Sample Input

Sample Output

6 1 3 2

Explanation

The minimum number of coins required is 6 with in it:
- minimum number of 5 Rupee coins = 1
- minimum number of 2 Rupee coins = 3
- minimum number of 1 Rupee coins = 2

Using these coins, we can form any value with in the given value and itself, like below:

Here the given value is 13

For 1 = one 1 Rupee coin
For 2 = one 2 Rupee coin
For 3 = one 1 Rupee coin and one 2 Rupee coins
For 4 = two 2 Rupee coins
For 5 = one 5 Rupee coin
For 6 = one 5 Rupee and one 1 Rupee coins
For 7 = one 5 Rupee and one 2 Rupee coins
For 8 = one 5 Rupee, one 2 Rupee and one 1 Rupee coins
For 9 = one 5 Rupee and two 2 Rupee coins
For 10 = one 5 Rupee, two 2 Rupee and one 1 Rupee coins
For 11 = one 5 Rupee, two 2 Rupee and two 1 Rupee coins
For 12 = one 5 Rupee, three 2 Rupee and one 1 Rupee coins
For 13 = one 5 Rupee, three 2 Rupee and two 1 Rupee coins

JAVA Code for Coin Distribution Problem

import java.util.*;
public class Main
{
  public static void main (String[]args)
  {
    System.out.println ("Enter the Number");
    Scanner s = new Scanner (System.in);
    int number = s.nextInt ();
    int one = 0, two = 0;
    int five = (number - 4) / 5;
    if (((number - 5 * five) % 2) == 0)
      {
	one = 2;
      }
    else
      {
	one = 1;
      }
    two = (number - 5 * five - one) / 2;
    System.out.println (one + two + five);
    System.out.println (five);
    System.out.println (two);
    System.out.println (one);

  }
}

Coin Distribution Problem in few other Coding Languages

C

To find the solution of Coin Distribution Problem in C Programming language click on the button below:

C++

To find the solution of Coin Distribution Problem in C++ Programming language click on the button below:

C++

Python

To find the solution of Coin Distribution Problem in Python Programming language click on the button below:

Python

One comment on “JAVA Program for Coin Distribution Problem”

Gyanendra
// Java Solution :-
import java.util.*;
public class Main
{
public static void main(String[] args) {
Scanner scn=new Scanner(System.in);
int n=scn.nextInt();

int five=(n-4)/5;
n=n-(5*five);

int one=n%2==0 ? 2:1;
n=n-one;

int two=n/2;

System.out.println(“5- “+five+”\n2- “+two+”\n1- “+one);

}
}

1

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