How to solve Command Line Arguments Coding Questions

Command Line Arguments Questions for TCS

For TCS Command Line Arguments Programs let us consider this, if you wanted to write a basic C program then you would’ve written a main function that would’ve looked like – 

int main()
{
        // some code in Command Line Arguments Questions for TCS C Compiler
}

However in command line arguments we write like this – 

int main(int argc, char *argv[]){

1. argc – It is know as Argument Count and as clear from the name it stores the Count of number of Arguments.
2. argv[] – Pointer, contains location of all the values(arguments).
3. *argv[] – Array of values of all the arguments.
4. They are parameters/arguments supplied to the program when it is invoked.

Thus, now we have two things for TCS C Compiler

1. Total Count of number of Arguments.
2. All the values/pointer location of arguments stored in an array.

Now, you will need one more thing i.e. atoi();

• atoi(); – Converts string into int and atoi(argv[i]); will give the value of argument at ith location in int type format.

Now you can use an int val = atoi(argv[i]); to store the value and then print it with printf(); function.

To pass command line arguments, we typically define main() with two arguments : first argument is the number of command line arguments and second is list of command-line arguments.

int main(int argc, char *argv[]) { /* ... */ }

or

int main(int argc, char **argv[]) { /* ... */ }

Quick Facts for TCS Command Line Arguments Programs

argv[0] contains the default value, not the input value so –

• All for loops must start from i = 1.
• You must use the following condition

if(argc == 1){
// do nothing since, there are no arguments, maybe ask for arguments?
}else{
// code to apply logic and print values.
}

• provided+1 +1 for file.exe
• argv[argc] is a NULL pointer.
• argv[0] holds the name of the program.
• argv[1] points to the first command line argument and argv[n] points last argument.

Command Line Arguments Questions for TCS Rules for Coding Section Steps:
There is only one question for 20 minutes.

1. It has 10 attempts(We can compile only 10 times).
2. We must start our code from the scratch.
3. The coding platform is divided into two, one for writing the code and other for output. We should write the whole program.
4. We can’t use any input functions like scanf(), getch(), getchar().
5. The input to be provided should be read as command line arguments.

We must only print exact output in Command Line Arguments Questions for TCS Procedure –

1. Output must not be re-framed by extra words.
2. If there is any error, the error will be shown in the output dialog box.
3. The errors are clearly mentioned.
4. If there are no errors, a message like “compiled successfully” will be printed.
5. Along with that they will mention four test cases are ‘passed’ or maybe ‘failed’.
6. They are indicated like private and public test cases. They have not mentioned what is the test case, which is difficult to understand in TCS Command Line Arguments Programs.

Dont Compile again and again since compiler takes 25 seconds and each time you compile 25 seconds will become lesser in the time you have to code.