Python program for Converting digit/number to words

Converting digit/number to words in Python

Here, in this page we will discuss the program for Digit/number to words in Python .The conversion of numbers in words is just a conversion of numeric values to the English format of reading numbers. This code supports the conversion of numbers from 0 – 9999 in English format.

digit/number to words in python

Method 1 Algorithm

We will be using num2words library for this

Run
from num2words import num2words

# Most common usage.
print(num2words(11098))

# can also specify this for -th format
print(num2words(11098, to='ordinal'))

Method 2 Algorithm

  •  Taking input as a string from the user.
  •  Check the length of the input.
  •  if the length is zero print ’empty’ and if the length is greater than 4 print ‘give a string of specific length’
  •  if length id between 1 – 4, Create arrays for different values.
  •  Checking the length of the string.
  •  According to the place of the digit, we will show the output.

Code in Python

Run
def convert_to_words(num):
 
    l = len(num)
 
    # Base cases
    if (l == 0):
        print("empty string")
        return
 
    if (l > 4):
        print("Length more than 4 is not supported")
        return
 
    single_digits = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
 
    two_digits = ["", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]
 
    tens_multiple = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]
 
    tens_power = ["hundred", "thousand"]
 
    print(num, ":", end=" ")
 
    if (l == 1):
        print(single_digits[ord(num[0]) - 48])
        return
 
    x = 0
    while (x < len(num)): if (l >= 3):
            if (ord(num[x]) - 48 != 0):
                print(single_digits[ord(num[x]) - 48],
                      end=" ")
                print(tens_power[l - 3], end=" ")
 
            l -= 1
 
        else:
 
            if (ord(num[x]) - 48 == 1):
                sum = (ord(num[x]) - 48 +
                       ord(num[x+1]) - 48)
                print(two_digits[sum])
                return
 
            elif (ord(num[x]) - 48 == 2 and
                  ord(num[x + 1]) - 48 == 0):
                print("twenty")
                return
 
            else:
                i = ord(num[x]) - 48
                if(i > 0):
                    print(tens_multiple[i], end=" ")
                else:
                    print("", end="")
                x += 1
                if(ord(num[x]) - 48 != 0):
                    print(single_digits[ord(num[x]) - 48])
        x += 1
 
 
# Driver Code
convert_to_words("1121") 

Output:

1121 : one thousand one hundred twenty one

2 comments on “Python program for Converting digit/number to words”


  • Bhoma

    one = [ “”, “one “, “two “, “three “, “four “,
    “five “, “six “, “seven “, “eight “,
    “nine “, “ten “, “eleven “, “twelve “,
    “thirteen “, “fourteen “, “fifteen “,
    “sixteen “, “seventeen “, “eighteen “,
    “nineteen “];

    ten = [ “”, “”, “twenty “, “thirty “, “forty “,
    “fifty “, “sixty “, “seventy “, “eighty “,
    “ninety “];

    # This code only the range of 0 to 100
    def numToWords(n, s):

    str = “”;
    if (n > 19):
    str += ten[n // 10] + one[n % 10];
    else:
    str += one[n];
    if (n):
    str += s;

    return str;

    # This is for 20 to almost infinity

    # Function to print a given number in words
    def convertToWords(n):
    out = “”;
    out += numToWords((n // 10000000), “crore “);
    out += numToWords(((n // 100000) % 100),”lakh “);
    out += numToWords(((n // 1000) % 100),”thousand “);
    out += numToWords(((n // 100) % 10),”hundred “);

    if (n > 100 and n % 100):
    out += “and “;
    out += numToWords((n % 100), “”);

    return out;

    print(convertToWords(8000));