# Python Program for Addition of two fractions

Here, in this page we will discuss program for addition of two fractions in python. For this purpose we need to ask the user to enter two fractional values where each fraction must consist a Numerator and a Denominator. ### Concept

For understanding this in a better way lets suppose an example :

Suppose, First fraction consist of 1 as numerator and 3 as denominator, and Second fraction consist of 3 as numerator and 9 as denominator.

(1 / 3) + (3 / 9) = (6 / 9) = (2 / 3)

• Find LCM of 3 and 9 and the result will be 9.
• Multiply 3 in first fraction : (3 / 9) + (3 / 9)
• Add both fractions and then the result will be : (6 / 9)
• Now simplify it by finding the HCF of 6 and 9 and the result will be 3.
• So divide 6 and 9 by 3 and then the result will be : (2 / 3)

### Algorithm

• Initialize variables of numerator and denominator
• Take user input of two fraction
• Find numerator using this condition (n1*d2) +(d1*n2 ) where n1,n2 are numerator and d1 and d2 are denominator
• Find denominator using this condition (d1*d2) for lcm
• Calculate GCD of a this new numerator and denominator
• Display a two value of this condition x / gcd, y/gcd ### Python code

Run
```def findGCD(n1, n2):
gcd = 0
for i in range(1, int(min(n1, n2)) + 1):
if n1 % i == 0 and n2 % i == 0:
gcd = i
return gcd

# input first fraction
num1, den1 = map(int, list(input("Enter numerator and denominator of first number : ").split(" ")))

# input first fraction
num2, den2 = map(int, list(input("Enter numerator and denominator of second number: ").split(" ")))

lcm = (den1 * den2) // findGCD(den1, den2)

sum = (num1 * lcm // den1) + (num2 * lcm // den2)

num3 = sum // findGCD(sum, lcm)

lcm = lcm // findGCD(sum, lcm)

print(num1, "/", den1, " + ", num2, "/", den2, " = ", num3, "/", lcm)
```

### Output

```Enter numerator and denominator of first number : 14 10
Enter numerator and denominator of second number: 24 3
14 / 10 + 24 / 3 = 47 / 5```

For similar Questions click on the given button.

• Ganesh

g1nume = int(input(‘Enter the numerator for 1st fraction :’))
g1deno = int(input(‘Enter the denominator for the 1st fraction :’))
g2nume = int(input(‘Enter the numerator for 2nd fraction :’))
g2deno = int(input(‘Enter the denominator for the 2nd fraction :’))

n = g1deno*g2deno
o = g2deno*g1nume
h = g1deno*g2nume
k = o + h

print(k, ‘/’, n) 2
• Ganesh

Print(k, ‘/’, n) — unknowingly typed in same line 1
• Ganesh

#Easy to understand
g1nume = int(input(‘Enter the numerator for 1st fraction :’))
g1deno = int(input(‘Enter the denominator for the 1st fraction :’))
g2nume = int(input(‘Enter the numerator for 2nd fraction :’))
g2deno = int(input(‘Enter the denominator for the 2nd fraction :’))

n = g1deno*g2deno
o = g2deno*g1nume
h = g1deno*g2nume
k = o + h

print(k, ‘/’, n) 1
• Gorgulls

For same denominator , The above code is not fully combined:;

f1_nume = int(input(‘Enter the numerator for 1st fraction :’))
f1_deno = int(input(‘Enter the denominator for the 1st fraction :’))
f2_nume = int(input(‘Enter the numerator for 2nd fraction :’))
f2_deno = int(input(‘Enter the denominator for the 2nd fraction :’))
#check if denominators are same
if(f1_deno == f2_deno):
Fraction1 = f1_nume + f2_nume
#print
print(‘Addition of two fractions are :’,Fraction1 ,”/”,(f1_deno))
#if denominators are not same
else:
#to find the sum
#denominators should be same
#apply cross Multiplication
Fraction2 = (f1_nume * f2_deno) + (f2_nume * f1_deno)
print(‘Addition of fractions are :’,(Fraction2),”/”, (f1_deno * f2_deno)) 0
• KIRA

Can it Be done like this cause this is more easy:
nume1 = int(input(“Enter Number : “))
deno1 = int(input(“Enter Number : “))
nume2 = int(input(“Enter Number : “))
deno2 = int(input(“Enter Number : “))

x = (nume1*deno2) + (nume2*deno1)
y = deno1 * deno2
print(“{}/{}”.format(x, y)) 0