Aricent Profit and Loss Problems with Solutions

In one kg there are 5 heads of corn so one kg maize corns are 20 Rs.
cost price of 1 head corn is 20/5 that is 4 Rs.
the selling price of 1 corn is 8.
in one day we should get profit 200 Rs.
let x be no. of maize corn should be sold to get 200 Rs as profit.
We know that profit =SP-CP.
So 8x-4x=200 then x=50.....

To check the Explanation: Visit this link -
https://prepinsta.com/salesman-liberty-sell-hair-dryer-store-price-rs/

Revenue=price * sales
here price decreased by 25% and sales increased by 20%
so take A= -25(bcas reduce) B= +20
by applying net percentage formule we get the answer
revenue=A+B+AB/100;
so -25+20+(-25*20)/100
ans is -10% decrease 10%

(300*15)/100=45
so 300-45=255
and again (255*10)/100=25.5
so 255-25.2=229.5

discount for belt=75*(25/100)=18.75
discount for shirt=1999*(25/100)=499.75
discount for shawl=2900*(25/10)=725.00
Total discount =18.75+499.75+725.00
=> 3730.50
Total shopping=75+1999+2900
=> 4974.00
net pay amount =4974.00-1243.50
=> 3730.50

let total profit x.
distributed Profit: 2/3*x.
A/B=17:13
A's Share in profit : 17/30*2x/3 = 17x/45
B's Share in profit : 13/30*2x/3 = 13x/45

given A=B+800
=>17x/45=13x/45+800
=> 4x/45=800
=>x=9000(ans)
Total profit =9000
Shared Profit: for A : 3400
for B : 2600.

for 1st condition : s is face value on s it gives 30% profit after giving 20% discount.so cp will be :40s/65;
2nd case if mark price b m then it gives 25% profit .so cp woultd be 4m/5
hence,4m/5=40s/65 =>m=10s/13.then it is evident that s will be a multiple of 13.so ans is option 1>>> 1287.

let cost price of article be x rs
then profit=x*(1/4) =x/4 & SP= x+ x/4 =5x/4

if the article is sold at a profit of 1/4 of SP then new profit = 1/4 * 5x/4 = 5x/16

so 5x/16 -x/4 = 50
=> x/16 =50
=> x=800

so, the cost of the article = 800 rs

E1 = C1 * P1

1.6 E1 = C2 * 0.8 P1

5/8 =5*C1 / 4*C2
1/2 = C1 / C2 -> 100% increase

For, 15 cups of coffee for Rs 1000.

Tea - 24 cups in 6oo rs
so, 1 cup Tea - 25 rs

coffee - 15 cups in 1000rs
so, 1 cup coffee - RS 66 but also possible value- 66,65,64,63
choose value 63 because we want to purchase maximum cups of coffee.

Here,
2200 Rs and 8 cups of tea and X cups of coffee

8*(25)+X *(63) = 2200
x * (63) = 2000
max value for X =31 So, X * 63 < 2000

Ans is 31 cups of coffee.