MindTree Coding Pattern Questions – 3

July 8, 2019

Ques. Print the following Pattern and get the output to match test cases?

To print the pattern like
 for n=3
the program should print
1 1 1 2
3 2 2 2
3 3 3 4

Program in C++

#include <iostream>

using namespace std;

int main()
{
   int n=3,c=n-1;
   for(int i=1;i<=n;i++)
   {
       if(i%2==0)
       cout<<c++;
       for(int j=1;j<=n;j++)
       {
           cout<<i;
       }
       if(i%2!=0)
       cout<<c++;
       cout<<“\n”;
   }
  
  
   return 0;
}

Program in C

#include 
int main(void) {
int i,j,n=3,c=n-1;
for(i=1;i<=n;i++)
{
if(i%2==0)
printf(“%d”,c++);
for(j=1;j<=n;j++)
{
printf(“%d”,i);
}
if(i%2!=0)
printf(“%d”,c++);
printf(“\n”);
}

return 0;
}

Please do comment the code in other languages :).

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7 comments on “MindTree Coding Pattern Questions – 3”


  • Adit

    Program in JAVA:
    import java.util.Scanner;
    public class Prog61
    {
    public static void main(String args[])
    {
    Scanner sc=new Scanner(System.in);
    int n=sc.nextInt();
    int count1=1;
    int count2=n-1;
    int a=0,b=n;
    int flag=0;
    for(int i=0;i<n;i++)
    {
    for(int j=0;j<n+1;j++)
    {

    if(flag==0)
    {

    if(j==n){
    System.out.print(count2+" ");
    flag=1;
    break;
    }
    else{
    System.out.print(count1+" ");
    }
    }
    else
    {
    if(j==n)
    {
    System.out.print(count2+" ");
    flag=0;
    break;
    }
    else
    {
    System.out.print(count1+" ");
    }
    }
    }
    count1=count1+1;
    count2=count2+1;
    System.out.println();
    }
    }
    }

    0

  • SAGEN SOREN

    public class mindtreePattern3 {

    public static void main(String[] args) {
    // TODO Auto-generated method stub

    int i,j,n=3,c = n-1;

    for(i = 1 ;i <= n ; i++)
    {
    if(i % 2 == 0)
    System.out.print(" "+c++);
    for(j = 1; j <= n ; j++)
    {
    System.out.print(" "+i);

    }if(i % 2 != 0) {
    System.out.print(" "+c++);

    }
    System.out.println("");
    }

    }

    }

    0

  • ajay bogam

    # python-3

    t=int(input())
    val=1
    for i in range(1,t+1):
    if(i%2==0):
    val+=1
    print(val,end=’ ‘)
    val-=1
    for j in range(t):
    print(val,end=” “)
    print()
    val+=1
    else:
    for j in range(t):
    print(val,end=” “)
    val+=1
    print(val)

    0

  • Anmol

    static void mindtreePattern3(int n)
    {
    int k=1;
    for(int i=0;i<n;i++)
    {
    for(int j=0;j0)
    System.out.print(k);
    else
    {
    System.out.print(k+1);
    }
    }
    }
    System.out.println();
    k++;
    }
    }

    1

  • psp gamer

    #include
    int main()
    {
    int n,i,j;
    scanf(“%d”,&n);
    for(i=1;i=1;j–)
    {
    if(i%2==0)
    {
    if(j==n+1)
    {
    printf(“%d”,i+1);
    }
    else
    {
    printf(“%d”,i);
    }
    }
    else
    {
    if(j==1)
    {
    printf(“%d”,i+1);
    }
    else
    {
    printf(“%d”,i);
    }
    }
    }
    printf(“\n”);
    }
    return 0;
    }

    1