MindTree Coding Pattern Questions – 3

July 8, 2019

Ques. Print the following Pattern and get the output to match test cases?

To print the pattern like
 for n=3
the program should print
1 1 1 2
3 2 2 2
3 3 3 4

Program in C++

#include <iostream>

using namespace std;

int main()
{
   int n=3,c=n-1;
   for(int i=1;i<=n;i++)
   {
       if(i%2==0)
       cout<<c++;
       for(int j=1;j<=n;j++)
       {
           cout<<i;
       }
       if(i%2!=0)
       cout<<c++;
       cout<<“\n”;
   }
  
  
   return 0;
}

Program in C

#include 
int main(void) {
int i,j,n=3,c=n-1;
for(i=1;i<=n;i++)
{
if(i%2==0)
printf(“%d”,c++);
for(j=1;j<=n;j++)
{
printf(“%d”,i);
}
if(i%2!=0)
printf(“%d”,c++);
printf(“\n”);
}

return 0;
}

Please do comment the code in other languages :).

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14 comments on “MindTree Coding Pattern Questions – 3”


  • INDELA

    #include

    using namespace std;

    int main()
    {
    int n,c=0;
    cin>>n;

    for(int i=1;i<=n;i++)
    {
    if(i%2==1)
    {
    cout<<++c<<" "<<c<<" "<<c<<" "<<++c<<endl;
    }
    else
    {
    cout<<++c<<" "<<–c<<" "<<c<<" "<<c<<" "<<endl;
    }
    }

    return 0;
    }


  • Naveen

    n = 3

    for i in range(1,n+1):
    if i%2 != 0 :
    for j in range(n):
    print(i , end = ”)
    print(i+1,end = ”)
    print(‘\n’)

    else:
    print(i+1,end = ”)
    for k in range(n):
    print(i,end = ”)
    print(‘\n’)

    code in python


  • maddy

    #include
    int main()
    {
    int num,p,i,j,k=1;
    scanf(“%d”,&num);
    p=num+1;
    j=1;
    for(i=1;i<=num;i++)
    {
    if(i%2==1)
    {
    while(k<=num)
    {
    printf("%d ",j);
    k++;
    }
    printf("%d ",j+1);
    }
    else
    {
    printf("%d ",j+1);
    while(k<=num)
    {
    printf("%d ",j);
    k++;
    }

    }
    j++;
    k=1;
    printf("\n");
    }
    }


  • ammula

    Program in Python
    r= 3
    for i in range(1,r+1):
    if i%2!=0:
    for j in range(1,r+1):
    print(i,end=”)
    for j in range(0,1):
    i+=1
    print(i,end=”)
    else:
    for j in range(0,1):
    i+=1
    print(i,end=”)
    i-=1
    for j in range(1,r+1):
    print(i,end=”)

    print(‘\r’)


  • priya

    import java.util.Scanner;
    class User{
    public static void main(String[] args) {
    Scanner s=new Scanner(System.in);
    int n=s.nextInt();
    int k=1;
    for(int i=1;i<=n;i++)
    {
    for(int j=1;j<=n+1;j++) {
    if(i%2!=0) {
    if(j<=n)
    System.out.print(k+" ");
    else
    System.out.print(k+1+" ");
    }
    else {

    if(j==1) {

    System.out.print(k+1+" ");
    }
    else {
    System.out.print(k+" ");
    }
    }
    }
    System.out.println();
    k++;
    }
    }
    }


  • Adit

    Program in JAVA:
    import java.util.Scanner;
    public class Prog61
    {
    public static void main(String args[])
    {
    Scanner sc=new Scanner(System.in);
    int n=sc.nextInt();
    int count1=1;
    int count2=n-1;
    int a=0,b=n;
    int flag=0;
    for(int i=0;i<n;i++)
    {
    for(int j=0;j<n+1;j++)
    {

    if(flag==0)
    {

    if(j==n){
    System.out.print(count2+" ");
    flag=1;
    break;
    }
    else{
    System.out.print(count1+" ");
    }
    }
    else
    {
    if(j==n)
    {
    System.out.print(count2+" ");
    flag=0;
    break;
    }
    else
    {
    System.out.print(count1+" ");
    }
    }
    }
    count1=count1+1;
    count2=count2+1;
    System.out.println();
    }
    }
    }


  • SAGEN SOREN

    public class mindtreePattern3 {

    public static void main(String[] args) {
    // TODO Auto-generated method stub

    int i,j,n=3,c = n-1;

    for(i = 1 ;i <= n ; i++)
    {
    if(i % 2 == 0)
    System.out.print(" "+c++);
    for(j = 1; j <= n ; j++)
    {
    System.out.print(" "+i);

    }if(i % 2 != 0) {
    System.out.print(" "+c++);

    }
    System.out.println("");
    }

    }

    }


  • ajay bogam

    # python-3

    t=int(input())
    val=1
    for i in range(1,t+1):
    if(i%2==0):
    val+=1
    print(val,end=’ ‘)
    val-=1
    for j in range(t):
    print(val,end=” “)
    print()
    val+=1
    else:
    for j in range(t):
    print(val,end=” “)
    val+=1
    print(val)


  • Anmol

    static void mindtreePattern3(int n)
    {
    int k=1;
    for(int i=0;i<n;i++)
    {
    for(int j=0;j0)
    System.out.print(k);
    else
    {
    System.out.print(k+1);
    }
    }
    }
    System.out.println();
    k++;
    }
    }


  • psp gamer

    #include
    int main()
    {
    int n,i,j;
    scanf(“%d”,&n);
    for(i=1;i=1;j–)
    {
    if(i%2==0)
    {
    if(j==n+1)
    {
    printf(“%d”,i+1);
    }
    else
    {
    printf(“%d”,i);
    }
    }
    else
    {
    if(j==1)
    {
    printf(“%d”,i+1);
    }
    else
    {
    printf(“%d”,i);
    }
    }
    }
    printf(“\n”);
    }
    return 0;
    }


    • Rishabh

      #include
      int main() {
      int i,j,n;
      scanf(“%d”,&n);
      for(i=1;i<=n;i++)
      {
      for(j=1;j<=4;j++)
      {
      if(i%2!=0)
      {
      if(j<=3)
      {
      printf("%d",i);
      }
      else
      {
      printf("%d",i+1);
      }
      }
      else
      {
      if(j==1)
      {
      printf("%d",i+1);
      }
      else
      {
      printf("%d",i);
      }
      }
      }
      printf("\n");
      }
      return 0;
      }


    • INDELA

      #include

      using namespace std;

      int main()
      {
      int n,c=0;
      cin>>n;

      for(int i=1;i<=n;i++)
      {
      if(i%2==1)
      {
      cout<<++c<<" "<<c<<" "<<c<<" "<<++c<<endl;
      }
      else
      {
      cout<<++c<<" "<<–c<<" "<<c<<" "<<c<<" "<<endl;
      }
      }

      return 0;
      }