MAQ Software Coding Questions and Answers

May 5, 2023

MAQ Software Coding Round Questions

MAQ Software Coding Questions and Answers asked in the Hiring Process of MAQ which is an Computer Based Online Recruitment Test.

Before you go through the test process, we would like to tell you some of the guidelines to attempt the test. Please note that the information on this page is solely based on the campus recruitment process. It may differ for off-campus or on -campus region to region.

About MAQ Software

MAQ Software is a group of software professionals who help Global 2000 firms speed data-driven changes. They speed up software efforts that help our customers revolutionise their businesses by utilising data analytics, cloud technologies, and data science.

They are dedicated to achieving client goals and growing our customer base. 90% of our consumers are regulars. For Fortune 500 firms, MAQ Software provides cutting-edge software solutions.

Their solutions make use of artificial intelligence (AI), cognitive services like Azure Machine Learning, the newest cloud computing trends like Microsoft Azure and Amazon Web Services, big data and advanced business intelligence features of SQL Server and Power BI, as well as the newest form factors like iOS and Android.

MAQ Software Eligibility Criteria

MAQ Software hired for two positions that is Associate Software Engineer and Software Engineer 1. We have tabulated the eligibility criteria below in the tabulated format for both the profiles.

MAQ Software	Associate Software Engineer	Software Engineer 1
Batch	2023	2023
Course	B. Tech./B.E. (CSE/ IT) M. Tech./M.E. (CSE/IT) BCA + MCA/ B.Sc. (IT) + MCA/ B.Sc. (CS) + MCA	B. Tech./B.E. (CSE/ IT) M. Tech./M.E. (CSE/IT) BCA + MCA/ B.Sc. (IT) + MCA/ B.Sc. (CS) + MCA
Role	Associate Software Engineer	Software Engineer 1
Education	60% plus or equivalent in Computer Science/Information Technology 60% plus in 10th and 12th No active backlogs	60% plus or equivalent in Computer Science/Information Technology 60% plus in 10th and 12th No active backlogs
Stipend/CTC:	36k PM/ 7.5 LPA	36k PM/ 7.5 LPA
Work location	Noida/Hyderabad/Mumbai in office	Noida/Hyderabad/Mumbai in office

Segregation od Posts at MAQ Software The selection of both the position is based on interview.

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Sample MAQ Software Coding Questions

Question 1 : Individual Character Count

Problem Statement :

You’re given a string where multiple characters are repeated consecutively. You’re supposed to reduce the size of this string using mathematical logic given as in the example below :

Input :
aabbbbeeeeffggg

Output:
a2b4e4f2g3

Input :
abbccccc

Output:
ab2c5

C++

JAVA

Python

C++

Run

#include <bits/stdc++.h>

using namespace std;

int main() {
    string s;
    getline(cin, s);
    map < char, int > m;
    for (auto i: s) m[i]++;
    for (auto i: m) cout << i.first << i.second;
}

JAVA

Run

import java.util.*;
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String str = sc.nextLine();
        int i, j, k = 0, count = 0;
        String uni = new String("");
        for (i = 0; i < str.length(); i++) {
            count = 0;
            for (j = 0; j <= i; j++) {
                if (str.charAt(i) == str.charAt(j)) {
                    count++;
                }
            }
            if (count == 1) {
                uni = uni + str.charAt(i);
            }
        }
        for (i = 0; i < uni.length(); i++) {
            count = 0;
            for (j = 0; j < str.length(); j++) {
                if (uni.charAt(i) == str.charAt(j)) {
                    count++;
                }
            }
            if (count == 1) {
                System.out.printf("%c", uni.charAt(i));
            } else {
                System.out.printf("%c%d", uni.charAt(i), count);
            }
        }
    }
}

Python

Run

s = input()
i = 1
c = 1
while i < len(s):
    if s[i] == s[i - 1]:
        c += 1
    else:
        print(s[i - 1], end="")
        print(c, end="")
        c = 1
    i += 1
print(s[i - 1], end="")
print(c)

Question 2 : Set Bit

Problem Statement :

You are given an integer, N. You have to turn it into the binary representation of it, and find out how many set bits are there in the binary representation.

Input Format:
The first line contains the integer.

Output Format:
One line containing an integer denoting the number of setbits.

Constraints:
1<=N<=10^9

Sample Input:
8
Output:
1

Output Description:
8 in binary is 1000.

C++

JAVA

Python

C++

Run

#include <bits/stdc++.h>

using namespace std;

int main() {
    int n, ans = 0;
    cin >> n;
    while (n) {
        n &= (n - 1);
        ans++;
    }
    cout << ans;
}

JAVA

Run

import java.util.*;
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int count = 0;
        while (n != 0) {
            if ((n & 1) == 1)
                count++;
            n = n >> 1;
        }
        System.out.println(count);
    }
}

Python

Run

n = int(input())
ans = 0
while n:
    n &= n - 1
    ans += 1
print(ans)

Question 3 : Formatting large Products

Problem Statement: Rohan is weak in mathematics. He is giving mathematics Olympiad , but he got stuck in one of the question .Help rohan to solve the question.In Question there are two positive integer A and B. You have to find the product of all integer between A and B which is represented in the form C=D*10^E , where C is the product of numbers , D and E are non-negative integers and the last digit of D is non-zero.

Function Description

Complete the function formatProducts in the editor below, formatProduct must return a string that represents C in the above described form.
Function has the following parameters
A: an integer
B: an integer

Constraints

A will between 1 and 1,000,000 . Inclusive.
B will be between A and 1,000,000. Inclusive.

Sample Input 0

Sample Output 0

12 * 10^1

Explanation

1*2*3*4*5=120 = 12 * 10^1

Sample Input 1

Sample Output 1

18144 * 10^2

Explanation

3*4*….*10=1814400 =18144 * 10^2

Java

Python

Java

Run

import java.util.*;
public class Main
{
  public static String formatProducts (int a, int b)
  {
    int result = 1;
    for (int i = a; i <= b; i++)
        result = result * i;
    int temp = result;
    int power = 0;
    while ((result % 10) == 0)
      {
	power = power + 1;
	result = result / 10;
      }
    return result + " * 10^" + power;
  }
  public static void main (String[]args)
  {
    Scanner sc = new Scanner (System.in);
    int a = sc.nextInt ();
    int b = sc.nextInt ();
    System.out.println (formatProducts (a, b));
  }
}

Python

Run

def formatProducts(L,H):
    a=1
    for i in range(L,H+1):
        a=a*i 
    c=0
    while(True):
        if a%10!=0:
            break
        else:
            c+=1 
        a=a//10
    return (str(a)+" * 10^"+str(c))
L=int(input())
H=int(input())
print(formatProducts(L,H))

Question 4 : Copycat in exam (R->Medium)

Rahul copies in the exam from his adjacent students. But he doesn’t want to be caught, so he changes words keeping the letter constant. That means he interchanges the positions of letters in words. You are the examiner and you have to find if he has copied a certain word from the one adjacent student who is giving the same exam, and give Rahul the markings he deserves.

Note that: Uppercase and lowercase are the same.

Input Format:

First line with the adjacent student’s word

Second line with Rahul’s word

Output Format:

0 if not copied

1 if copied

Constraints:

1<=Length of string<=10^6

Sample Input:

CAR

ACR

Sample Output:

Java

Python

C++

Java

Run

import java.util.*;
public class Main
{
  public static void main (String[]args)
  {
    Scanner sc = new Scanner (System.in);
    String s1 = sc.next ();
    String s2 = sc.next ();
      s1 = s1.toUpperCase ();
      s2 = s2.toUpperCase ();
    char arr1[] = s1.toCharArray ();
      Arrays.sort (arr1);
    char arr2[] = s2.toCharArray ();
      Arrays.sort (arr2);
    String res1 = new String (arr1);
    String res2 = new String (arr2);
    if (res1.equals (res2))
        System.out.println ("1");
    else
        System.out.println ("0");
  }
}

Python

Run

s=input()
s1=input()
s=s.lower()
s=sorted(s)
s1=s1.lower()
s1=sorted(s1)
if s1==s:
    print(1)
else:
    print(0)

C++

Run

#include<bits/stdc++.h>
using namespace std;
int main()
{
    string s2,s1;
    cin>>s1>>s2;
    transform(s1.begin(),s1.end(),s1.begin(),::tolower);
    transform(s2.begin(),s2.end(),s2.begin(),::tolower);
    sort(s1.begin(),s1.end());
    sort(s2.begin(),s2.end());
    cout<< (s2==s1);
}

Question 4 : Minimum Occurrence (R->Medium)

Problem Statement :
Given a sting , return the character that appears the minimum number of times in the string. The string will contain only ascii characters, from the ranges (“a”-”z”,”A”-”Z”,0-9), and case matters . If there is a tie in the minimum number of times a character appears in the string return the character that appears first in the string.

Input Format:
Single line with no space denoting the input string.

Output Format:
Single character denoting the least frequent character.

Constraints:
Length of string <=10^6

Sample Input:
cdadcda

Sample Output:
c

Explanation:
C and A both are with minimum frequency. So c is the answer because it comes first with less index.

C++

JAVA

Python

C++

Run

#include <bits/stdc++.h>
using namespace std;
unordered_map < char,int > F;


int main()
{
    string s;
    int m=INT_MAX;
    cin >> s;
    for(auto i:s) F[i]++;
    for(auto i:F) m=min(m,i.second);
    for(auto i:s)
        if(F[i]==m)
            {
                cout << i;
                break;
            }
}

JAVA

Run

import java.util.*;
public class Main
{
  public static void main(String[] args)
{
   Scanner sc=new Scanner(System.in);
   String str=sc.next();
   char arr[]=str.toCharArray();
   int temp[]=new int[256];
    for(int i=0;i < arr.length;i++) { temp[arr[i]]++; } int min=Integer.MAX_VALUE; int index=0; for(int i=255;i >=  0;i--)
    {
       if(temp[i]==0)
        continue;
       min=Math.min(min,temp[i]);
      } 
    for(int i=0;i < arr.length;i++)
   {
       if(min==temp[arr[i]])
     {
        System.out.println(arr[i]);  
        break;
     }
  }
}
}

Python

Run

s=input()
ans=[]
for i in s:
    ans.append(s.count(i))
print(s[ans.index(min(ans))])

FAQs on MAQ Coding Questions

Question 1: Is it hard to crack MAQ Interview Process?

Candidates who have appeared for MAQ Interview process claimed that Technical Interview of MAQ Software is bit Hard because they generally ask questions based on DSA, DBMS, OOPs concept, etc with other core subjects of Computer Science.

Question 2: What are steps involved in MAQ Software's recruitment process?

MAQ Software’s Recruitment Process mainly consists of 3 steps:

Online Aptitude and Coding Assessment.
Technical Interview
HR Interview

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MAQ Software Coding Questions and Answers

MAQ Software Coding Round Questions

About MAQ Software

MAQ Software Eligibility Criteria

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Sample MAQ Software Coding Questions

Question 1 : Individual Character Count

Question 2 : Set Bit

Question 3 : Formatting large Products

Function Description

Constraints

Sample Input 0

Sample Output 0

Explanation

Sample Input 1

Sample Output 1

Explanation

Question 4 : Copycat in exam (R->Medium)

Question 4 : Minimum Occurrence (R->Medium)

FAQs on MAQ Coding Questions

Question 1: Is it hard to crack MAQ Interview Process?

Question 2: What are steps involved in MAQ Software's recruitment process?

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