Java Program to Count The Sum of Numbers in a String

October 14, 2022

Count the sum of number in a string

For counting the sum of a digit in a given string, we’re going to code a java program in this article. Take a string input from the user and store it in a variable called “s” in this case. We are using isdigit method of Character class to check that particular character is a digit or not if that character is a digit then add that character to the sum variable to find sum.

 

Capitalize The First and Last Letter in java

Here we need to count the sum of the number present in the string in the string we can have alphabets as well as some digits so we need to find the sum of the digits. Lets take one example to understand this.

  • Input string :- “4PREP2INSTAA6”
  • Output :- 12

As in the given string “4PREP2INSTAA6” the number of character that is a number is 4+2+6=12 hence the output is 12.

First we can iterate through the string and check if the character is in range of ‘0’ to ‘9’ if that is the case we will add it to the sum and then print the result.

Using inbuild function we can do the same that is iterate throughout the string and check if the character is a digit or not using isdigit() function.

Algorithm ​

  • Take a string input from user and store it in the variable called “s”.
  • Take a i for loop start from i=0 to i<s.length().
  • Check the condition that character is digit or not.
  • Calculate sum of each digit and store it in the sum variable.
  • After that simply print the value of sum.

Java​ Code (Count the sum of number in a string)

Run 
import java.util.Scanner;
public class Main {
   public static void main(String[] args) {
   String s ="4PREP2INSTAA6";
   int sum=0;
   for (int i = 0; i < s.length(); i++) {
      if(Character.isDigit(s.charAt(i))) 
      sum=sum+Character.getNumericValue(s.charAt(i));
      }
   System.out.println("Sum of all the digit present in String : "+sum);
  }
}

Output

Sum of all the digit present in String : 12

Method 2

Run 

public class Main {
public static void main(String[] args) {
String str="4PREP2INSTAA6";

int sum=0;
for(int i=0;i<str.length();i++){ 
if(str.charAt(i)>='0' && str.charAt(i)<='9'){
sum+=(str.charAt(i)-'0');
}
}
System.out.println("Sum of all digits " +sum );
}
}

Output

Sum of all digits 12
 
 

Toggle each character in a string

Count the number of vowels

Length of the string without using strlen() function

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10 comments on “Java Program to Count The Sum of Numbers in a String”


  • amitgupta742001

    import java.util.*;
    public class exercise {
    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    String str = sc.nextLine();

    int count=0;
    for(int i=0;i<str.length()-1;i++){
    count++;
    }
    System.out.print(count);
    }
    }


  • Akhil

    import java.util.*;
    public class Main
    {
    public static void main(String[] args) {
    Scanner scan=new Scanner(System.in);

    System.out.println(“Enter string”);
    String str=scan.nextLine();
    int sum=0;
    for(int i=0;i=’0′ && ch<='9')
    {
    sum=sum+(ch-'0');
    }
    }
    System.out.println("Sum="+sum);
    }
    }


  • Ankitha

    public class SumOfNumInString {
    public static void main(String args[]) {
    Scanner sc = new Scanner(System.in);
    String str = sc.nextLine();
    String str1 =””;int l;int sum=0;
    str1 = str.replaceAll(“[^0-9]”, “”);
    int n = Integer.parseInt(str1);
    while(n>0) {
    l=n%10;
    sum=sum+l;
    n=n/10;
    }
    System.out.println(sum);
    }


  • Vijaykhede

    public class Main {
    public static void main(String[] args){
    Scanner sc=new Scanner(System.in);
    System.out.println(“enter String”);
    String s=sc.next();
    int i,ch,sum=0;
    String s1=””;
    for(i=0;i=’0’&&ch<='9')
    {
    s1=s1+(char)ch;
    sum=sum+Integer.parseInt(s1);
    }
    s1="";
    }
    System.out.println(sum);
    }
    }


  • Srinibash

    import java.util.Scanner;
    public class p10 {
    public static void main(String[] args){

    Scanner sc = new Scanner(System.in);
    System.out.println(“Enter a String”);
    String s1 = sc.nextLine();
    int sum=0;
    s1=s1.replaceAll(“[^0-9]”,””);
    System.out.println(s1);
    Integer number = Integer.valueOf(s1); //convert from String to integer
    for(int i =0;i< s1.length();i++){
    sum= sum +number % 10;
    number=number/10;
    }
    System.out.println(sum);
    }
    }


  • Kaushik

    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    String s = sc.nextLine();
    int sum = 0;
    for(int i=0; i=’0′ && s.charAt(i)<='9'){
    sum = sum + (s.charAt(i) – '0');
    }
    }
    System.out.println(sum);
    }


  • adityarajsingh1878610003

    String str = “pr2ep4in5st1”;
    int res = 0;
    str = str.replaceAll(“[^0-9]”,””);
    char[] ch = str.toCharArray();
    for(int i = 0;i<ch.length;i++){
    res = res + Character.getNumericValue(ch[i]);
    }
    System.out.println("res);

    I think this is easier !!


  • adityarajsingh1878610003

    String str = “pr2ep4in5st1”;
    int res = 0;
    str = str.replaceAll(“[^0-9]”,””);
    char[] ch = str.toCharArray();
    for(int i = 0;i<ch.length;i++){
    res = res + Character.getNumericValue(ch[i]);
    }
    System.out.println(" "+res+" ");

    I think this is easier !!


  • SIDDHANT

    public class MyClass {
    public static void main(String args[]) {

    String s=”pr2ep4in5st1″;
    int sum=0;
    for(int i=0;i<s.length();i++)
    {
    if(Character.isLetter(s.charAt(i)))
    {
    continue;
    }
    else
    {
    sum+=Integer.parseInt(""+s.charAt(i));
    }
    }
    System.out.println(sum);

    }
    }


  • Subhajit

    import java.util.Scanner;
    public class Main
    {
    public static void main(String[] args) {
    Scanner obj=new Scanner(System.in);
    System.out.println(“enter a string:”);
    String str=obj.nextLine();
    int n=str.length();
    int s=0;
    s=s+n;
    System.out.println(“sum:”+s);
    }
    }