Java program to check frequency of characters in a string
Check Frequency of Characters in a string
Finding the frequency of a character in a string, means we have to check how many times a particular character is present in that string. Here, we have coded a Java Program for the same. Let’s take an example of a string “prepinsta” . In which we have to check that how many times each of the characters gets repeated in the string.

Algorithm
- Take string input from user and store it in the variable called “str”.
- After that make freq array having size of length of string.
- Convert string to char array .
- Run for loop start from i=0 to str<length() store 1 to freq array.
- Run j loop start from i=i+1 to j<str.length().
- check condition if(string[i] == string[j]) then do freq[i]++ and set string[j]=’0′ .
- After that display frequency of character one by one.
Code in Java (Check Frequency of Characters)
import java.util.Scanner; public class FrequencyOfCharactersInAString { public static void main(String[] args) { Scanner sc =new Scanner(System.in); System.out.print("Enter String : "); String str = sc.nextLine(); int[] freq = new int[str.length()]; int i, j; //Converts given string into character array char string[] = str.toCharArray(); for(i = 0; i <str.length(); i++) { freq[i] = 1; for(j = i+1; j <str.length(); j++) { if(string[i] == string[j]) { freq[i]++; //Set string[j] to 0 to avoid printing visited character string[j] = '0'; } } } //Displays the each character and their corresponding frequency System.out.println("Characters and their corresponding frequencies"); for(i = 0; i <freq.length; i++) { if(string[i] != ' ' && string[i] != '0') System.out.println(string[i] + "-" + freq[i]); } } }
Output
Enter String : prepinsta
Characters and their corresponding frequencies
p-2
r-1
e-1
i-1
n-1
s-1
t-1
a-1
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import java.util.*;
public class main {
public static void main(String[] args) {
String str = “prepinsta”;
Set set = new HashSet();
for(char c : str.toCharArray()){
set.add(c);
}
List list = new ArrayList(set);
for(int i=0;i<list.size();i++){
int count = 0;
for(int j=0;j<str.length();j++){
if(list.get(i) == str.charAt(j)){
count++;
}
}
System.out.println(list.get(i)+" = "+count);
}
}
}
class Demo {
public static void main(String[] args) {
String str = “helloo worldhhhh”;
str=str.replaceAll(” “,””);
boolean[] visited = new boolean[str.length()];
for (int i = 0; i < str.length(); i++) {
if (!visited[i]) {
int c = 1;
char ch = str.charAt(i);
for (int j = i + 1; j < str.length(); j++) {
if (ch == str.charAt(j)) {
c++;
visited[j] = true;
}
}
visited[i] = true; // Mark current character as visited
System.out.print(ch + ":" + c + " ");
}
}
}
}
public class HelloWorld {
public static void main(String[] args) {
System.out.println();
String str=”prepinsta”;
char c[]=str.toCharArray();
char temp;
for(int i=0;i<c.length;i++)
{
for(int j=i+1;jc[j])
{
temp=c[i];
c[i]=c[j];
c[j]=temp;
}
}
}
for(int i=0;i<c.length;i++)
{
int count=1;
while(i<c.length-1 && c[i]==c[i+1])
{
count++;
i++;
}
System.out.println(c[i]+" ; "+count+" ");
}
}
}
public static void main (String[]args)
{
HashMap map = new HashMap();
String str = “prepinsta”;
char ch[] = str.toCharArray();
for(Character ch1 : ch){
map.put(ch1, map.getOrDefault(ch1, 0)+1);
}
System.out.println(map);
}
}