# Program to find Strong numbers in 1 to 100 in Java

## Strong Number in 1 to 100 in Java

Here, in this page we will discuss the program to find Strong Number in 1 to 100 in Java. We will discuss the algorithm along its code in java

## Algorithm :

• Run a loop  from [1, 100] and check if any number between the range is strong number or not.
• To check a number is strong or not,
• Store the factorial for digits 0 to 9 in an array.
• Run a loop till the number is greater than 0, set
• Sum = sum + (n%10)!.
• At last check if(sum==n)
• If yes then print the corresponding number, else check for the next number.

## Time and Space Complexity :

• Time Complexity : O(n)
• Space Complexity : O(1)

### Code in Java

Run
```class Main{

static int[] factorial = { 1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362880 };

public static boolean isStrong(int N)
{

String num = Integer.toString(N);

int sum = 0;

for (int i = 0; i < num.length(); i++) {
sum += factorial[Integer.parseInt(num.charAt(i) + "")];
}

return sum == N;
}

public static void printStrongNumbers(int N)
{

for (int i = 1; i <= N; i++) {

if (isStrong(i)) {
System.out.print(i + " ");
}
}
}

// Driver Code
public static void main(String[] args)
{
int N=100;

// Function Call
printStrongNumbers(N);
}
}```

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