Java program to find out the quadrant in which the given co-ordinate lie
Quadrant in which the given co-ordinate lie
There are 2 axis (say x and y axis) in a two-dimensional planes. Based on values either positive or negative, a point is decided to lie on which co-ordinate. We need simple if-else statements to write a Java program to find out the quadrant in which the given co-ordinate lie. Generally there are four quadrants.
Working :
According mathematics quadrants rules:
- X is positive integer as well as Y is also positive a integer it signifies first quadrant.
- X is negative integer but Y is positive integer it signifies second quadrant.
- X is negative integer as well as Y is also negative integer it signifies third quadrant.
- X is positive integer but Y is negative integer it signifies fourth quadrant.
Algorithm :
- Get value of x & y
- If ( x>0 and y>0 ) First Quadrant
- If ( x<0 and y>0 ) Second Quadrant
- If ( x<0 and y<0 ) Third Quadrant
- If ( x>0 and y>0 ) Fourth Quadrant
- If ( x=0 and y=0 ) Origin
- If ( x!=0 and y=0 ) x-axis
- If ( x>0 and y>0 ) y-axis
Java code
Run
import java.io.*; public class Main { public static void main (String[] args) { int x=-3, y=-33; //find true condition of first quadrant if(x>0 && y>0) System.out.println("Quadrant I"); //find second quadrant else if(x<0 && y>0) System.out.println("Quadrant II"); //To find third quadrant else if(x<0 && y<0) System.out.println("Quadrant III"); //To find Fourth quadrant else if (x > 0 && y < 0) System.out.println("Quadrant IV"); //To find dose not lie on origin else if (x == 0 && y == 0) System.out.println("Origin"); //On x-axis else if (y==0 && x!=0) System.out.println("x-axis"); //On y-axis else if (x==0 && y!=0) System.out.println("y-axis"); } }
Output
Insert the value for variable X and Y : -3 -33 point (-3, -33) lies in the Third quadrant
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