Decimal to binary conversion using Java

September 29, 2022

Decimal to Binary conversion using Java

In this article we will create program for decimal to binary conversion using java. For this purpose we need to ask a decimal number from user and convert that decimal number to its binary equivalent form and then print the converted number on to the screen.
Decimal to binary

Working

For conversion, we divide the decimal number by 2 and get the quotient 
for the next iteration and continuously store the remainder value in an 
array in reverse order till the decimal number is greater than 0. For better understanding with an example just have a look towards the diagram 
shown at the right.

Example : Decimal number 5 = 101 in binary representation.
Decimal to binary conversion using java

Octal to Decimal conversion

Hexadecimal to Decimal conversion

Decimal to Binary conversion

Decimal to Octal Conversion

Decimal to Hexadecimal Conversion

Binary to Octal conversion

Algorithm

  • Initialize a empty array name binary
  • While decimal is greater then zero
  • If decimal is even r equals to 0 and else set 1
  • Append r to binary
  • Set decimal as half of its value

Java Code

Run 
//Java program to convert decimal number to binary number
public class Main
{
	public static void main(String args[])
	{   
		//Decimal Number
		int decimal = 12;
		//integer array for storing binary digits 
		int binary[] = new int[20];
		int i = 0; 
		//writing logic for the conversion 
		while(decimal > 0)
		{       
			int r = decimal % 2;
			binary[i++] = r;
			decimal = decimal/2;
		}
		//printing result
		System.out.print("Binary number : ");
		for(int j = i-1 ; j >= 0 ; j--)
		System.out.print(binary[j]+"");
	}
}

Output

Binary number : 1100

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8 comments on “Decimal to binary conversion using Java”


  • siddeshaob2001

    package pripInsta;

    public class BinarytoDecimal {

    public static void main(String[] args) {
    // TODO Auto-generated method stub
    String str=”1110″;

    System.out.println(“in Binary: “+str);

    int n=Integer.parseInt(str, 4);

    System.out.println(“in Decimal: “+n);

    int x=22;
    System.out.println(“Decimal “+x);

    String s2=Integer.toBinaryString(x);

    System.out.println(“to binary “+s2);
    }
    }

    0

  • Tridip

    import java.text.NumberFormat.Style;
    import java.util.*;
    public class Perfect{

    public static List decimaltobinary(int decimal){

    List a = new ArrayList();

    while(decimal >0){

    int rem = decimal %2;

    a.add(rem);

    decimal /=2;

    }
    Collections.reverse(a);

    return a;

    }

    public static void main(String[] args){

    List hold;

    hold =decimaltobinary(6);
    System.out.println(hold);

    }
    }

    0

  • vaishyambresh

    // Without Using extra space

    import java.util.Scanner;
    public class a_31_Decimal_to_Binary {

    public static int binary(int dec) {
    int bin = 0 ;
    int pow = 0 ;
    while(dec != 0){
    int rem = dec % 2 ; // remainder when we are dividing of 2
    bin = bin + rem * (int)Math.pow(10, pow) ;

    dec = dec/2 ;
    pow++ ;
    }

    return bin ;
    }

    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in) ;
    System.out.println(“Enter a decimal : “);
    int dec = sc.nextInt() ;

    System.out.println(“Binary of ” + dec + ” = ” + binary(dec));

    }
    }

    0

  • Prithuraj

    Scanner sc = new Scanner(System.in);
    int a = sc.nextInt();
    int remain = a;
    String ans = “”;
    while (remain > 0) {
    ans += remain % 2;
    remain = remain / 2;
    }
    System.out.println(new StringBuffer(ans).reverse());
    sc.close();

    0

  • swatikadas6

    import java.util.Scanner;

    class Beginner {
    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    System.out.print(“Enter your number:”);
    int decimal = sc.nextInt();
    int count=0;
    int binary =0;
    int rem;
    int temp;
    double res;
    temp=decimal;
    while(temp!=0)
    {
    rem = temp%2;
    res = Math.pow(10,count);
    binary = (int) (binary+rem*res);
    temp/=2;
    count++;
    }
    System.out.println(“Binary Number “+binary);
    sc.close();
    }
    }

    0

  • swatikadas6

    import java.util.Scanner;

    class Beginner {
    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    System.out.print(“Enter your number:”);
    int decimal = sc.nextInt();
    int count=0;
    int binary =0;
    int rem;
    int temp;
    double res;
    temp=decimal;
    while(temp!=0)
    {
    rem = temp%2;
    res = Math.pow(10,count);
    binary = (int) (binary+rem*res);
    temp/=10;
    count++;
    }
    System.out.println(“Binary Number “+binary);
    sc.close();
    }
    }

    0

  • ECE

    I think this code will also do the conversion.
    public class decitobinary {
    public static void main(String[] args) {
    Scanner s = new Scanner(System.in);
    int deci = s.nextInt();
    StringBuilder binary = new StringBuilder();
    while(deci>1){
    binary.append(deci%2);
    deci/=2;
    }
    binary.append(deci);
    binary.reverse();
    System.out.println(binary);
    }
    }

    0