Coin Puzzle 3

Coin Puzzle 3

Suppose we have 3 glasses and 10 coins. The problem is to place odd number of coins in each glass i.e. each glass should contain coins and the number of coins in each glass must be odd and total coins which will be used must be equal to 10.

Solution:

Information Provided:

• Number of Glass: 3
• Number of Coins: 10
• Requirement: Place coins in glass in such a manner that in each glass there is odd number of coins and all 10 coins are used.

Number of Glass = 3
Number of Coins = 10

We have arrange all coins in all the glasses such that each glass has odd numbered coinss It is not possible to use all 10 coins with each glass having odd number of coins. Therefore, we must think out of box. In the 1st glass place 5 coins which is odd, after that in 2nd glass place 2 coins and in the 3rd glass place 3 coins which is odd. Now, place the entire 3rd glass inside 2nd glass. Indirectly, now 2nd glass contains 5 coins which is odd in nature.

Arranging 10 Coins in 3 glasses so that there is odd number of Coins in each glass is impossible, so we have to think differently to solve this question .

First Step:

• Put 5 coins in the 1st glass, which is an odd number.
• Now put 2 coins in the 2nd glass.
• At last  put 3 coins in the 3rd glass,which is again an odd number.

Second Step:

• Now there are 2 glass with odd number of coin, i.e., 1st and 3rd glass. But glass 2 still have 2 coins which is an even number.
• Now what we can do is put the 3rd glass which has 3 coins into 2nd glass as there is no instruction that we can not merge 2 glasses. Now as we put 3rd glass into 2nd glass now the total number of coins in 2nd class is 5 which is an odd number.

Number of Glass = 3
Number of Coins = 10

We have arrange all coins in all the glasses such that each glass has odd numbered coins.

First Step
Number of Coins in 1st Glass = 5
Number of Coins in 2nd Glass = 2
Number of Coins in 3rd Glass = 3

After 1st Step only 2 glasses have odd number of Coins i.e., 1st and 3rd.

Second Step
Number of Coins in 1st Glass = 5
Number of Coins after putting 3rd glass in 2nd in 2nd =
= 2 + 3 = 5 