Hsbc Age Aptitude questions

Ans: 1+2+3+4+5+6+7+8+9+10 – (4+8) =43

Ans. A

In each segment of the diagram are a pair of letters, one of which is the same distance from the start of the alphabet as the other is from the end.

On each watch, the sum of the digits shown equals 8.

On each watch, the sum of the digits shown equals 8.

A B and C will share the amount of Rs. 2340 in the ratio of the amounts of work done by them.

As A takes 6 days to complete the job, if A works alone, A will be able to complete  th of the work in a day.

Similarly, B will complete  and C will complete  of the work.

So, the ratio of the work done by A : B : C when they work together will be equal to 

Multiplying the numerator of all 3 fractions by 24, the LCM of 6, 8 and 12 will not change the relative values of the three values.
We get  = 4 : 3 : 2.
i.e., the ratio in which A: B : C will share Rs.2340 will be 4 : 3 : 2.

Hence, C’s share will be  = Rs.520.

Find the total weight of the nuts:

1 nut = 100 g

90 nuts = 100 x 90 = 9000g = 9kg

Find the total weight of the bolts:

1 bolt = 150 g

100 bolts = 150 x 100 = 15000g = 15kg

Find the total weight of the nuts and bolts:

Total weight = 9  + 15 = 24 kg

Find the weight of the empty box:

Weight of the entire box = 35.5 kg

Empty box = 35.5 - 24 = 11.5 kg

Answer: The weight of the empty box is 11.5 kg

 

Length of rectangle = 14 cm
Width of rectangle = 10 cm
Area of rectangle = 140 cm²

Length of rectangle after it is reduced by 'x' cm = 14 - x cm
Width of rectangle after it is increased by 'x' cm = 10 + x   cm
The rectangle is now a square as given in the problem statement, thus :-

Thus each side is of equal length,

Thus length = breadth

14 - x = 10 + x
-2 x = - 4

Thus, x=2

Substitute x= 2 in 14 - x OR 10 + x

Each side of the square is 12 cm long

Thus area of the square is 144 cm²

Change in area is = 144 - 140 = 4 cm²

 

We're told that a motorcycle stuntman rides over the vertical walls of a circular well at an average speed of 54 kph for 5 minutes (in simple terms, he's riding his motorcycle in a circle) and the radius of the well is 5 meters. We're asked for the distance the stuntman travels. While this question is a bit awkwardly-worded, it's essentially just a rate question.

Since we know the motorcycle's speed and time traveled, the fact that it's going in a circle is irrelevant (and by extension, so is the radius of the circle).

5 minutes = 5/60 = 1/12 of an hour

Distance = (54 Km/hour)(1/12 hour)
Distance = 54/12 = 4 6/12 = 4.5 km

The volume of the larger cube = 53 = 125 cm3.

The volume of each of the smaller cubes = 13 = 1 cm3.

Therefore, one would get 125 smaller cubes.

The surface area of the larger cube = 6a2 = 6(52) = 6 * 25 = 150

The surface area of each of the smaller cubes = 6 (12) = 6.

Therefore, surface area of all of the 125, 1 cm3 cubes = 125 * 6 = 750. Therefore, the required ratio = 150 : 750 = 1 : 5

Customer can choose 3 out of 5 flavors 5C3=10;
Customer can choose 1 out of 2 cone type 2C1=2;

Total # of combinations possible 10*2=20.

Given that the average of $5$ numbers is $6$, their sum is $5\times 6=30$.

Given that the average of the $3$ selected numbers is $8$, their sum is $3\times 8=24$.

So the remaining two numbers add up to $30-24=6$ and their average is $\frac{6}{2}=3$

1/2^-4

Solution:-

In 3 hours the swimming pool can be filled to the capacity.

Then, in 1 hour the part of the swimming pool can be filled = 1/3th part

And,

In 6 hours, the drain pipe completely drain the swimming pool

Then, in 1 hour, the drain pipe will completely drain the part of the swimming pool =

1/6th part

When both pipes are open,

⇒ 1/3 - 1/6 = 1/6

So, 1/6th of the swimming pool is filled in 1 hour.

Hence it will take 6 hours to completely fill the pool to capacity.

Let OT be the tower.

Therefore, Height of tower = OT = 30 m
Let A and B be the two points on the level ground on the opposite side of tower OT.

Then,
angle of elevation from A = TAO = 45^o
and angle of elevation from B = TBO = 60^o
Distance between AB = AO + OB = x + y (say)
Now, in right triangle ATO,
tan 45^o = 
=> x =  = 30 m
and in right traingle BTO
tan 60^o = 
=> y =  = 17.32 m

Hence, the required distance = x + y = 30 + 17.32 = 47.32 m

P(1+r)^2 = 144/121 * P
r = 1/11

P+Prt = 3P
P(1+rt) = 3P; rt = 2;
t = 2/(1/11) = 22

3/p=6
6p=3
p=3/6
p=1/2

3/q=15
15q=3
q=3/15
q=1/5

p-q=1/2-1/5
=5-2/10
=3/10

The volume of the rectangular tank is:

10 inches by 8 inches  by 4 inches

10 × 8 × 4 = 320 inches³

The volume of the smaller cubical tanks of side 3 inches:

3 inches by 3 inches by 3 inches

3 × 3 × 3 = 27 inches ³

Divide the volume of the bigger tank by the smaller tank to find the number of smaller tanks that will be needed:

320 inches ³ / 27 inches ³   = 11. 851851 tanks

Since you do not have a fraction of the small tank, you will need 12 tanks. However, the 12th tank will not be filled.

The number of tanks required is 12

 

Let the radius of circles be r and R respectively

If the ratio of their area = 169 : 196

Then,

2 * pi * r^2/ 2 * pi * R^2 = 169/196

r^2 /R^2 = 169 * 196

Square rooting on both side

r / R = 13 /14

Hence the ratio of radii will be 13 : 14.

 

Let portion of sum is invested at 4% = x

Portion invested at 5% will be = (7200 - x)

Annual income is same from both the parts so,

4% of x = 5% of (7200 - x)

4x/100 = 5/100 (7200 - x)

4x = 36000 - 5x

4x + 5x = 36000

9x = 36000

x = 36000/9 = 4000

Part invested at 4% = 4000

Part invested at 5% = (7200 - 4000) = 3200

 

1cm=40 Kms
37.5cm=37.5×40kms
=actual distance between Bombay and Calcutta is 1500kms

Let the original number of workers in the group be 'x'

Therefore, the actual number of workers = x-7.

We know that the number of manhours required to do the job is the same in both the cases. Therefore, x (24) = (x-7).30 24x = 30x - 210 6x = 210 x = 35.

Therefore, the actual number of workers who worked to complete the job = x - 7 = 35 -7 = 28.

18= 3^2 x 2.
18^15= 3^30 x 2^15.
C.

fI they mean that two taps together have filled 2/5 (40%) of the tank in 20mins, then each fills 20% in 20mins, ie 1%/min and so one will take 60mins to fill the remaining 60%. If they mean that each of the taps alone fills 2/5 (40%) in 20mins, then each fills 2%/min and then one will fill the remaining 20% in 10min. Or if you assume they are connected to the same water supply so that when one stops the other doubles in flow then you have either 30mins or 5mins. The 'correct' answer apparently is 15mins

The usual way to find the compound interest is given by the formula A = .p(1+r/100)^n

In this formula,

A is the amount at the end of the period of investment

P is the principal that is invested

r is the rate of interest in % p.a

And n is the number of years for which the principal has been invested.

In this case, it would turn out to be A =1500(1+20/100)^3

= 2592.

Let’s try solving this Problem using ratio approach.
Amount of work done by 20 men = 24 women = 40 boys or 1 man = 1.2 woman = 2 boys.

xyz is negative because you are multiply an odd number of negative signs
x+y+z is of course negative. The sum of any two negative numbers is always negative.
x(y+z) will be positive, but it will not be odd.
Why is that? Because if x is even, then y+z will be odd, and odd number times an even number is even.
x - yz will be negative because the product of yz will be positive and your taking that away from a negative number, so that will be negative.

That leaves choice b

(104+16)(100-40)/(100+60+40)) = $36

Ans. D

A = Amy's current age
B = Beth's current age
C = Chelsea's Current age

B-5 = 3(A-5)
(B-10) = (C-10)/2

A = 5 + (B-5)/3

B = 10 + (C-10)/2

A = 5 + {[10+(C-10)/2] - 5}/3
A = 5 + (10 + C/2 - 5 - 5)/3
A = 5 + C/6

The first one n the list, c/6 + 5, is the correct choice

> b
a - b = 6
a + b = relative speed = 287/3.5 = 82

10 am to 1:30 pm = 3.5 hrs
what is a?

a = (82+6)/2 = 44

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The stock price dropped from 25to21 so it dropped 4.Thepercentagechangeisthechange(−4), as a fraction of the starting price ($25), and then expressed as a percentage. The drop as a fraction of the starting price is -4/25. Expressed as a percent this is

-4/25  100 = -16%.

lets assume wifes age= x years.
So, husband age = (x+6) years.
After 12 years of marriage
wifes age = (x+12) Years.
husbands age = (x+6+12) Years = (x+18) Years.
6/5(x+12)=(x+18)
=> 6x + 72 = 5x + 90
=> x = 18 Years.

According to the question,

We may have (1 black and 2 non-black) or (2 black and 1 non-black) or (3 black).

Required number of ways = (3C1 x 6C2) + (3C2 x 6C1) + (3C3)

= (45 + 18 + 1) = 64.

Explanation:

There are 8 students and the maximum capacity of the cars together is 9.

We may divide the 8 students as follows

Case I: 5 students in the first car and 3 in the second

Or Case II: 4 students in the first car and 4 in the second

Hence, in Case I: 8 students are divided into groups of 5 and 3 in 8C3 ways.

Similarly, in Case II: 8 students are divided into two groups of 4 and 4 in 8C4 ways.

Therefore, the total number of ways in which 8 students can travel is 8C3 + 8C4 = 56 + 70 = 126.

Explanation:

Suppose each subject has max marks of 100 and 10x,9x,8x,7x,6x are marks obtained in each subject, then

=> 40x = 300.

=> x= 7.5

Marks obtained in different subjects are 75, 67.5, 60.0, 52.5, 45.

Hence Marks obtained in different subjects are 75%, 67.5%, 60.0%, 52.5%, 45%.

So, he passed 4 subjects

Explanation:

Let the two no’s be a and b;

And, product of the no’s is ab.

If the each no's is increased by 2 then the new product will be

=> (a + 2) (b + 2) = ab + 2a + 2b + 4.

=> ab + 2(a+b) + 4

Hence, the new product increased by 4.

Explanation:

2x+y = 11 --> (1)

2y+z = 12 --> (2)

z+2x = 8 --> (3)

From (3)

=> z = 8-2x

From (2)

=> 2y+8-2x=12

=> y = x+2

From (1)

=> 2x+(x+2) = 11

=> 3x = 9

=> x = 3

=> y = 5

=> z = 2

=> 2x + 3y + 4z = 2(3) + 3(5) + 4(2) => 29.

Explanation:

Let the two-digit number is 10x+y

Product of the digits x*y=8

=> 10x+y+18=10y+x

On solving this we get X-y=-2

=> x+y=6

By solving the above two equations we get x=2 and y=4

Therefore the digit is 10*2+4=24.

Explanation:

According to the question,

speed of first train = 120/12 = 10 m/s

Let speed of second train be x m/s. As they are approaching each other, relative speed is (10+x) m/s.

Distance between each other is 120+120=240 m.

Time of crossing each other is 8 secs

=>240/(10+x) =8

=>x = 20m/s = 20*18/5 km/hr. = 72 kmph.

Explanation:

According to the question,

=> (200+160)/(V1-V2) = 60s.

So, V1 - V2 = 6 (V1 and V2 are the respective velocities)

In the Opposite direction the equation is

=> (200 + 160)/ (V1 + V2) =10s,

so, V1 + V2 = 36.

Solving, V1 = 21m/s and V2 = 15m/s.