DevSquare Quantitative Aptitude Profit and Loss Mixtures and Allegation Questions

cp of book=60
sp of book=70
profit=10
again cp=80
then loss =80-70=10

If she has x sons
each son has x-1 brothers.
Total no of grandchildren=x(x-1)
Total No OF Sons+Grandchildren= x+x(x-1)=x^2
=>Lucia\'s age is a perfect square between 50 and 70.
The only number that satisfies this condition is 64.

If you add the same mixture again,the ratio will still remain the same.
The question should be how much water to be added

In 10 litres, let quantity of milk = 2x and quantity of water = x
=> 2x + x = 10
=> x = 10/3 , 2x = 20/3

Let y litres of water be added to make the ratio 1:2
=> (20/3) / (10/3 + y) = 1 / 2
=> 40/3 = 10/3 + y
=> y = 10 liters

Therefore,10 liters of water to be added.

S.I = PTR/100
S.I =15000*9*2/100
S.I= 2700
C.I =P(1+r/100)^n -P
C.I= 12000(1+8/100)^2-12000
C.I=1996.8
total amount in 2 years
as interest = S.I +C.I
= 2700+1996.8
=4696.8

If x is earlier price, then

300/(x-5)- 300/x = 5
solving this , we get, x=20 or -15 out of which only 20 is acceptable.

let c.p of 1 mango Re 1.
then c.p of 18 mangoes= Rs 18
c.p of 20 mangoes Rs 20 = s.p of 18 mangoes
profit= s.p of 18 mangoes - c.p of 18 mangoes
=20 - 18
= 2
profit %= 2/18*100
=11.11 ans

Let’s say the C.P. of the goods is 100.

So marked price = 1.75 * 100 = 175

If the merchant doesn’t want any profit or loss, he may want to see the goods at Rs 100 only. i.e. he may want to give discount of Rs 75 at marked price of Rs 175.

Let’s say it’s x% discount

so 75 = x% of 175

75 = x * 175 / 100

x = 75 * 100/175 = 300/7 = 42.857 %

Then (126*1+135*1+2*x)/(1+1+2)= 153

on solving
261 + 2x = 4x153

2x = 612-261
x=351/2
X= 175.50

Let the cost of 1 litre milk be Rs 1.

milk in 1 litre mixture in 1st can = 3/4 litre

C.P.  of  1 litre  mixture  in 1st can = Rs 3/4 milk

in 1 litre mixture in 2nd can = 1/2 litre  milk

in 1 litre mixture in 2nd can = Rs 1/2 milk

in 1 litre of final mixture = 5/8 litre

Mean price = Rs 5/8 by the rule of alligation we have

x/y = ( 3/4 - 5/8)/(5/8 - 1/2)

x:y = 1/8: 1/8

x/y = 1/1

therefore we will mix 6 litre from each can

S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10%.

C.P. of 1 kg of the mixture = Rs. (100/110*68.20) =Rs. 62

By the rule of alligation, we have:

Cost of 1 kg tea of 1st kind. = Rs. 60,

Cost of 1 kg tea of 2nd kind.
= Rs. 65,

Mean Price = Rs. 63

i.e., the difference is of Rs. 3 and Rs. 2.

therefore, the ratio is 3:2