C++ Program to Replace all 0’s with 1 in a given integer
Program to Replace all 0’s with 1 in a given integer
Here we will discuss how to replace all the 0’s with 1 in a given integer using C++ programming language.
The concept is simple, find the digits of the integer. Compare each digit with 0 if the digit is equal to 0 then replace it with 1. Construct the new integer with the replaced digits.
The program for Implement a C Program to replace all 0’s with 1 in a given integer as an input, all the 0’s in the number has to be replaced with 1.
Question can come like Way 1
Write a code to change all zero's as one's (0s as 1s) in a given number? ex: 120014 needs to be printed as 121114
Question can come like Way 2
implement a c program to replace all 0's with 1 in a given integer as an input, all the 0's in the number has to be replaced with 1.
Algorithm
- Take Input in num and initialize a variable num with with value 0
- If num is equals to zero then update the value of num2 to 1
- Iterate using a while loop until num is greater then 0
- For each iteration initialize a variable rem and store unit digit of num
- If rem equals to 0 then set rem to 1
- Set num to num divide by 10 & num2 equals to num2*10+rem
- Reverse and print num2
C++ code
Run
#include<bits/stdc++.h> using namespace std; //main program int main() { int num,num2=0; cout<<"Enter number: "; //user input cin>>num; //checking for 0 input if(num == 0) num2=1; //converting 0 to 1 while(num>0) { int rem = num%10; if(rem == 0) rem = 1; num = num/10; num2=num2*10+rem; } num = 0 ; // Store the reverse of num2 while(num2>0){ int r = num2%10; num= num*10 + r; num2 /= 10; } //converted number cout<<"Converted number is: "<<num; return 0; }
Output
Enter number: 12090 Converted number is: 12191
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#include
#include
#include
using namespace std;
int main()
{
long int num;
string str;
cout<>num;
str=to_string(num);
for(int i=0;i<str.length();i++)
{
if(str[i]=='0')
{
str[i]='1';
}
}
cout<<str<<endl;
return 0;
}
int main()
{
int n, digit, i = 0;
cout <> n;
int arr[10000];
while (n != 0)
{
digit = n % 10;
n /= 10;
if (digit == 0)
{
arr[i++] = 1;
}
else
{
arr[i++] = digit;
}
}
for (int j = i – 1; j >= 0; j–)
{
cout << arr[j];
}
return 0;
}
int main()
{
int n, digit, i = 0;
// To take input from user
cout <> n;
// Declare an array
// To take size of an array as your requirement
int arr[10000];
//
while (n != 0)
{
digit = n % 10;
n /= 10;
// check digit == 0 and store 1 in it array, else store digit as it is
if (digit == 0)
{
arr[i++] = 1;
}
else
{
arr[i++] = digit;
}
}
// Printing an array in reverse order
for (int j = i – 1; j >= 0; j–)
{
cout << arr[j];
}
return 0;
}
#include
using namespace std;
int main()
{
int num;
cin>>num;
int n=num;
int i=10;
while(n!=0){
if(n%10==0)num=num+i/10;
n=n/10;
i=i*10;
}
cout<<num;
return 0;
}
#include
using namespace std;
int main()
{
string s;
cin>>s;
for(int i=0;i< s.length();i++)
{
if(s[i]=='0')
s[i]='1';
}
cout<<s;
return 0;
}
This code is wrong. It returns reversed string replacing 0 with 1.
Here is the correct code:
#include
using namespace std;
int calculateAddedValue(int number)
{
int result = 0;
int decimalPlace = 1;
if (number == 0)
{
result += (1 * decimalPlace);
}
while (number > 0)
{
if (number % 10 == 0)
{
result += (1 * decimalPlace);
}
number /= 10;
decimalPlace *= 10;
}
return result;
}
int replace0with1(int number)
{
return number += calculateAddedValue(number);
}
int main()
{
int num;
cout<>num;
cout << replace0with1(num);
}
Thank me later!
//C++
#include
#include
using namespace std;
int main()
{
string s;
cin>>s;
for(int i=0;i<s.length();i++)
{
if(s[i]=='0')
s[i]='1';
}
cout<<s<<endl;
}
//Python
n=input()
n1=n.replace(“0″,”1”)
print(n1)
//C++
#include
using namespace std;
int main()
{
int n,n1=0,i=1;
cin>>n;
while(n!=0)
{
int r=n%10;
if(r==0)
{
r=1;
}
n=n/10;
n1=n1+(r*i);
i=i*10;
}
cout<<n1<<endl;
}
//C++ Program
//Convert all 0’s to 1
#include
using namespace std;
//main program
int main()
{
int num,num2=0,i=1;
cout<>num;
//checking for 0 input
if(num == 0)
num2=1;
//converting 0 to 1
while(num>0)
{
int rem = num%10;
if(rem == 0)
rem = 1;
num = num/10;
num2=num2+rem*i;
i *=10;
}
//converted number
cout<<"Converted number is: "<<num2;
return 0;
}
/* c++ code for replacing all 0’s with 1 in given integer*/
#include
using namespace std;
int main()
{
int n,step=1,rem,res=0;
// input
cout<>n;
while (n!=0)
{
rem=n%10;
if (rem==0)
{
// if rem==0 replace it with 1
rem=1;
}
res+=rem*step;
n/=10;
step*=10;
}
// printing the result
cout<<res;
return 0;
}