Find all possible Palindromic Partitions of the given String in C++
All Possible Palindromic Partitions of the given String in C++
Today in this article we will discuss the program to Find all possible Palindromic partitions of the given String in C++ Programming Language. We will discuss both approach and code in this page.
Algorithm:
- We go through every substring starting from first character,
- Check if it is palindrome.
- If yes, then add the substring to solution.
- And recur for remaining part.
Code in C++
Run
#include<bits/stdc++.h>
using namespace std;
bool isPalindrome(string str, int low, int high)
{
while (low < high)
{
if (str[low] != str[high])
return false;
low++;
high--;
}
return true;
}
void allPalPartUtil(vector<vector<string>>&allPart, vector<string> &currPart, int start, int n, string str)
{
if (start >= n)
{
allPart.push_back(currPart);
return;
}
for (int i=start; i<n; i++)
{
if (isPalindrome(str, start, i))
{
currPart.push_back(str.substr(start, i-start+1));
allPalPartUtil(allPart, currPart, i+1, n, str);
currPart.pop_back();
}
}
}
void allPalPartitions(string str)
{
int n = str.length();
vector<vector<string> > allPart;
vector<string> currPart;
allPalPartUtil(allPart, currPart, 0, n, str);
for (int i=0; i<allPart.size(); i++ )
{
for (int j=0; j<allPart[i].size(); j++)
cout << allPart[i][j] << " ";
cout << "\n";
}
}
int main()
{
string str = "nitin";
allPalPartitions(str);
return 0;
}
Output :
n i t i n n iti n nitin
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C++ code
#include
using namespace std;
int main()
{
string str= “NITIN”;
for(int i=0;i<str.length();i++)
{
for(int j=i;j<str.length();j++)
{
if(i==j)
cout<<str[i]<<endl;
else{
string sub1= str.substr(i,j+1);
string sub2= sub1;
reverse(sub1.begin(),sub1.end());
//cout<<sub1<<" "<<sub2<<endl;
if(sub1==sub2)
cout<<sub1<<endl;
}
}
}
return 0;
}