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Print Right Diamond Number Pattern Type4
PRINTING PATTERN:
3
44
555
6666
555
44
3
PREREQUISITE:
Basic knowledge of C language and use of loops.
ALGORITHM:
- Take the number of rows as input from the user and store it in any variable.(‘r‘ in this case).
- Run a loop ‘r’ number of times to iterate through each of the rows. From i=0 to i<r. The loop should be structured as for( i=0 ; i
- Use an if condition to to print the top half of the pyramid. if (i<=r/2). Then run a loop from j=0 to j<=i. The loop should be structured as for(j=0 ; j<=i ; j++)
- Inside this loop print i+3.
- Else run a different loop from j=i to jThe loop should be structured as for( j=i ; j
- Inside this loop print (r-i+2).
- Inside the main loop print a newline to move to the next line after each row is printed.
Input:
3 4
Output:
3
44
555
6666
555
44
3
Input :
4 4
Output:
4
55
666
7777
666
55
4
Code 1
#include<stdio.h>
int main()
{
int i,j,s,N,count=0;
scanf("%d%d",&s,&N);
for(i=s;count<4;count++)
{
for(j=0;j<count+1;j++)
printf("%d",i);
printf("\n");
i=i+1;
}
for(i=s+N-2;count>0;count--)
{
for(j=0;j<count-1;j++)
printf("%d",i);
printf("\n");
i=i-1;
}
return 0;
}
#include
int main()
{
int rows,i,j=0,k=0,x=0;
printf(“enter the number of rows\n”);
scanf(“%d”,&rows);
for(i=1;i<=rows;i++)
{
j=0;
k=0;
if(i<=(rows+1)/2)
{
while(j(rows+1)/2)
{
while(k<(rows-i+1))
{
printf("%d",i-x);
k++;
}
x=x+2;
printf("\n");
}
}
return 0;
}