Print Number Star Square Pattern Type4

June 23, 2019

PRINTING PATTERN:

1*2*3*4

9*10*11*12

13*14*15*16

5*6*7*8

PREREQUISITE:

Basic knowledge of C language and use of loops.

ALGORITHM:

Take the number of rows/columns as input from the user and store it in any variable.(‘l‘ in this case).
Run a loop ‘l’ number of times to iterate through each of the rows. From i=0 to i<l. The loop should be structured as for( i=0 ; i<l : i++).
Run an if condition if( i==l) then increment count by l.
Run another if condition after the previous one if( i==l-1) then count should be equal to l.
run a nested loop to iterate through the columns. From j=0 to j<l. The loop should be structured as for(j=0 ; j<l ; j++).
increment count and run an if condition if(j==l-1).
if true then print count else print count and a star after it.
outside the nested loop reinitialize count=count-2*l then print a newline

CODE IN C:

#include<stdio.h>
int main()
{
int i,j,l,count=0; //declaring integers i,j for loops and l for number of rows
printf("Enter the number of rows/columns\n"); //Asking user for input
scanf("%d",&l); //Taking the input for number of rows
for(int i=0;i<l;i++) //Outer loop for number of rows
  {
    if(i==1)
      {
        count+=l;   
      }
    if(i==l-1)
      {
        count=l;
      }
    for(int j=0;j<l;j++) //Inner loop for number of columns in each row
     {
        count++;
        if(j==l-1)
          {
            printf("%d",count);
          }
        else
          {
            printf("%d*",count);
          }
     }
    printf("\n"); //Printing a new line after each row has been printed.
  }
}