Print Number Star Square Pattern Type1

June 23, 2019

PRINTING PATTERN:

1*2*3*4

5*6*7*8

9*10*11*12

13*14*15*16

PREREQUISITE:

Basic knowledge of C language and use of loops.

ALGORITHM:

1. Take the number of rows/columns as input from the user and store it in any variable.(‘l‘ in this case).
2. Run a loop ‘l’ number of times to iterate through each of the rows. From i=0 to i<l. The loop should be structured as for( i=0 ; i<l : i++).
3. Inside this loop run another nested loop to iterate through the columns. From j=0 to j<l. The loop should be structured as for(j=0 ; j<l ; j++).
4. increment count and the run an if condition if(j==l-1) .
5. which means if it is the last column then print only count
6. Else print a star after count
7. outside the loop print a newline

CODE IN C:

#include<stdio.h>
int main()
{
int i,j,l,count=0;                             //declaring integers i,j for loops and l for number of rows
printf("Enter the number of rows/columns\n");  //Asking user for input
scanf("%d",&l);                                //Taking the input for number of rows
for(int i=0;i<l;i++)                           //Outer loop for number of rows
  {
    for(int j=0;j<l;j++)                       //Inner loop for number of columns in each row
     {
       count++;                                //incrementing count
       if(j==l-1)                              //running if statement to not print star after the last column of digits
         {
           printf("%d",count);                //printing count
         }
       else                                   //else statement to print star after count
         {
           printf("%d*",count);               //printing star after count
         }
     }
   printf("\n");                               //Printing a new line after each row has been printed.
  }
}

TAKING INPUT:

DISPLAYING OUTPUT: