Print Hollow Pyramid Star Pattern

June 23, 2019

PRINTING PATTERN:

      *

    *  *

  *      *

*******

 

PREREQUISITE:

Basic knowledge of C language and use of loops.

ALGORITHM:

  1. Take the number of rows as input from the user and store it in any variable.(‘r‘ in this case).
  2. Run a loop ‘r’ number of times to iterate through each of the rows. From i=0 to i<r. The loop should be structured as for( i=0 ; i<r : i++).
  3.  Run a nested loop inside the main loop to print the spaces before the pyramid. From k=r to k>i +1. The loop should be structured as for( k=r; k>i+1 ;k–).
  4. Inside this nested loop print white space.
  5. Run another nested loop inside the main loop after the previous loop to print the stars in each column of a row. From j=0 to j<=i*2. The loop should be structured as for( j=0 ; j<i*2; j++).
  6. Inside this nested loop print star under the condition if(i==r-1).
  7. Under else use a nested if else statement to print the remaining stars if(j==0||j>=i*2) and else print white space
  8. Inside main loop move to the next line by printing a new line . printf(“/n”).

Code in C:

#include<stdio.h>
int main()
{
int i,j,k,r;     //declaring integer variables i,j,k for loops and r for number of rows
printf("Enter the number of rows :\n");     //Asking user for input
scanf("%d",&r);     //saving number of rows in variable r
for(i=0;i<r;i++)     //outer loop for number of rows
   {
      for(k=r;k>i+1;k--)//nested loop for number of spaces
         {
            printf(" ");//printing spaces
         }
      for(j=0;j<=i*2;j++)//nested loop for printing stars
         {
            if(i==r-1) //condition to print last row
               {
                  printf("*"); //printing stars in last row
               }
            else //else condition to print rest of the stars
               {
                  if(j==0||j>=i*2) //condition to print stars
                     {
                        printf("*"); //printing stars
                     }
                  else //else condition to print spaces
                     {
                        printf(" "); //printing spaces
                     }
               }
        }
     printf("\n"); //printing newline
   }
}

TAKING INPUT:
DISPLAYING OUTPUT:

12 comments on “Print Hollow Pyramid Star Pattern”


  • Mohammad

    #include

    int main()
    {
    int n;
    printf(“Enter n value”);
    scanf(“%d”, &n);
    for (int i = 0; i < n-1; i++)
    {
    for (int j = 0; j < n – i – 1; j++)
    {
    printf(" ");

    }
    for (int z = 0; z < (i * 2) + 1; z++)
    {
    if (z == 0 || z == (i * 2))
    {
    printf("*");
    }
    else {
    printf(" ");
    }
    }

    printf("\n");
    }
    for (int i = 0; i < (n*2)-1; i++)
    {
    printf("*");
    }
    }

    0

  • singhji012002

    #include
    using namespace std;

    int main()
    {
    int n;
    cout<<"Enter the any number : "<>n;

    for(int i=0; i<n; i++)
    {
    for(int j=0; j<n-1-i; j++)
    {
    cout<<" ";
    }
    for(int k=0; k<=2*i; k++)
    {
    if(i==0 || i==n-1 || k==0 || k==2*i)
    {
    cout<<"*"<<"";
    }
    else{
    cout<<" "<<"";
    }
    }
    cout<<endl;
    }
    }

    0

  • Mo

    C++ EASY SOLUTION
    #include

    using namespace std;

    int main()
    {
    int n;
    cin>>n;
    for(int i=1;ii ;k–)
    cout<<" ";
    for(int j=1;j<=2*i-1;j++)
    {
    if(j==1||j==2*i-1||i==n)
    cout<<"*";
    else
    cout<<" ";
    }
    cout<<endl;
    }

    return 0;
    }

    0

  • Mo

    C++ SOLITION IN EASY WAY—
    Coder- ADIL KHAN
    #include

    using namespace std;

    int main()
    {
    int n;
    cin>>n;
    for(int i=1;ii;k–)
    cout<<" ";
    for(int j=1;j<=2*i-1;j++)
    {
    if(j==1||j==2*i-1||i==n)
    cout<<"*";
    else
    cout<<" ";
    }
    cout<<endl;
    }

    return 0;
    }

    0

  • Poornachander

    n = int(input())
    k = n-1
    for i in range(n):
    if(i==0 or i==n-1):
    print(‘ ‘*k,’*’*((2*i)+1),’ ‘*k,sep=”)
    else:
    print(‘ ‘*k,’*’,’ ‘*((2*i)-1),’*’,’ ‘*k,sep=”)
    k-=1

    0

  • kandukuri

    /*
    * = 1 4
    *-* = 3 345
    *—* = 5 23456
    ******* = 7 1234567

    */
    #include
    int main()
    {
    int row; //4
    printf(“enter the number of rows : “);
    scanf(“%d”,&row);
    for (int i = 0; i i+1 ; j–) // spaces: 4,3,2 ; 4,3 ; 4
    {
    printf(” “);
    }

    for (int j = 0; j <= i*2 ; j++) // 0"0" ; 0"2" ; 0"4";0"6"
    {
    if (i==0 || j==0 || i==row-1 || j==i*2 )
    {
    printf("*");
    }
    else
    {
    printf(" ");
    }
    }
    printf("\n");
    }
    return 0;
    }

    2

  • NewTechHub

    Python 3

    n=int(input())

    k=2*n-2

    for i in range(n):
    for j in range(0,k):
    print(” “,end=”)

    k-=1

    for j in range(0,i+1):
    if (i == 0 or i == n – 1 or j == 0 or j == n – 1 or i==1 or i==j):
    print(‘*’, end=”)
    else:
    print(‘ ‘, end=”)
    print(end=’\n’)

    0

  • Clive Fernandes

    n = 4
    for i in range(n):

    if i == 0 or i == n-1:
    print(‘ ‘*(n -1 – i) + ‘*’ * (2*i + 1))
    else:
    print(‘ ‘*(n-1-i) + ‘*’+’ ‘*(2*i – 1) +’*’)

    4

  • Suyash Srivastava

    import java.io.*;
    import java.lang.*;
    class space
    {
    public static void main(String[]args)throws IOException
    {
    BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
    int n=Integer.parseInt(br.readLine());
    int k=0;
    for(int i=1;i<n;i++)
    {
    for(int j=i;j<n;j++)
    {
    System.out.print(" ");
    }
    while(k!=(2*i-1))
    {
    if(k==0||k==2*i-2)
    System.out.print("*");
    else
    System.out.print(" ");
    k++;
    }k=0;
    System.out.println(" ");
    }

    for(int i=0;i<2*n-1;i++)
    System.out.print("*");

    }
    }

    0