Print Half Diamond Star Pattern

PRINTING PATTERN:

*

**

***

****

***

**

*

PREREQUISITE:

Basic knowledge of C language and use of loops.

ALGORITHM:

  1. Take the number of rows as input from the user and store it in any variable.(‘r‘ in this case).
  2. Run a loop ‘r’ number of times to iterate through each of the rows. From i=0 to i<r. The loop should be structured as for( i=0 ; i<r : i++).
  3. Use an if condition to to print the top half of the pyramid. if (i<=r/2). Then run a loop from j=0 to j<=i. The loop should be structured as for(j=0 ; j<=i ; j++)
  4. Inside this loop print star.
  5. Else run a different loop from j=i to j<r. The loop should be structured as for( j=i ; j<r ; j++).
  6. Inside this loop print star.
  7. Inside the main loop print a newline to move to the next line after each row is printed.

CODE IN C:

#include<stdio.h>
int main()
{
int i,j,r;                     //declaring integer variables i,j for loops and r for number of rows
printf("Enter the number of rows(odd) :\n"); //Asking user for input
scanf("%d",&r);                     //taking number of rows and saving it in variable r
for(i=0;i<r;i++)                   // loop for number of rows
   {
      if(i<=(r/2))                //if condition to print the top half    
         {
            for(j=0;j<=i;j++)     // loop for stars per each row
               {
                  printf("*");    //printing stars
               }
         }
      else                        //else condition to print the bottom half
         {
            for(j=i;j<r;j++)      //loop for printing
               {
                  printf("*");    //printing stars
               }
         }

      printf("\n");      // printing newline after each row
   }
}

TAKING INPUT:

DISPLAYING OUTPUT:

5 comments on “Print Half Diamond Star Pattern”


  • Vijaykhede

    public class Main {
    public static void main(String[] args){
    int i,j,k,c=7,r=4;
    for(i=1;i<=c;i++){
    if(i<=4)
    {
    for(j=1;j<=i;j++)
    {
    System.out.print("*");
    }
    }
    else
    {
    for(j=1;j<=r+r-i;j++)
    {
    System.out.print("*");
    }
    }
    System.out.println();
    }
    }
    }


  • Arthi

    #python
    n = int(input())
    m = n//2+1
    for i in range(1,m+1):
    print(‘*’*i)
    for j in range(m-1,0,-1):
    print(‘*’*j)


  • Neha

    n=int(input(“enter number of rows:”))
    for i in range(0,n+1):
    print(“*”*(i+1))
    for i in range(n-1,-1,-1):
    print(“*”*(i+1))


  • Srivamshi

    JAVA:
    public class Main
    {
    void pattern(int n)
    {
    for(int i=0;i<n;i++)
    {
    for(int j=0;j<=i;j++)
    {
    System.out.print("*");
    }
    System.out.print("\n");
    }
    for(int k=1;k<n;k++)
    {
    for(int l=k;l<n;l++)
    {
    System.out.print("*");
    }
    System.out.print("\n");
    }

    }
    public static void main(String[] args) {

    int n=4;
    Main s=new Main();
    s.pattern(n);

    }
    }


  • sampath pendurthi

    code in python:
    n=int(input(“enter a number:”)
    o=””
    for i in range(0,n):
    o=”*”*(i+1)
    print(o)
    for i in range(0,n):
    print(o[0:n-i-1])